Answer:
c = 5505263.16 J/g.°C
Explanation:
Given data:
Mass of ring = 12 mg (12/1000 = 0.012 g)
Calories used = 30.0 cal (30.0 ×4184 = 125520 J)
Temperature increases = 1.9°C
Specific heat of ring = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
125520 J = 0.012 g×c ×1.9°C
125520 J = 0.0228 g.°C ×c
c = 125520 J / 0.0228 g.°C
c = 5505263.16 J/g.°C
Answer:
Petroleum and treating meals.
The percent by weight (w/w%) of sugar in soda : 6.216%
<h3>Further explanation</h3>
Given
mass of sugar = 23 g
total mass = 370 g
Required
the percent weight
Solution
%weight = (mass of solute : mass of solution) x 100%
solute = sugar
solution = solvent + solute = water + sugar
percent weight of sugar in soda :
= (23 : 370) x 100%
= 6.216 %
Answer:
The bonds between atoms in the reactants are rearranged to form new compounds in chemical reactions, but none of the atoms disappear and no new ones are formed. As a consequence, chemical equations must be balanced, meaning that the number and kinds of atoms must be the same on both sides of the reaction arrow.
Explanation:
<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
We are given:
Molarity of 
solution = 0.125 M
Volume of solution = 32.5 mL
Putting values in above equation, we get:
Hence, the number of moles of ammonium nitrate is 0.004 moles.
