Mass = force/acceleration
M=24/ 6
m=4 N
Since the system itself is giving off heat, this is a
reduction in the internal energy.
heat = - 25,000 J
Since work is being done on the system, therefore it is
an additional energy to the system. Work is given as:
work = - P dV
work = - 1.50 atm (6 L – 12 L)
work = 9 L atm
Since it is given that 1 L atm is equivalent to 101.3 J,
therefore the total energy added is:
energy due to work = 9 L atm (101.3 J / 1 L atm)
energy due to work = 911.7 J
Therefore the total change in internal energy is the sum
of heat and energy due to work:
Change in internal energy = - 25,000 J + 911.7 J
Change in internal energy = - 24,088.3 J
<span>Therefore, approximately 24.1 kJ of energy is lost by the
system in the total process.</span>
<span>
</span>
<span>Answer:</span>
<span>-24.1 kJ</span>
Answer:
Oxygen cycle
Explanation:
The components of the reservoirs of oxygen that are exchange in our environment is the oxygen cycle
It suggests the movement of oxygen between the living and non-living parts.
- The cycle does not account for oxygen that is trapped and cannot be exchanged in nature.
- Oxygen is important component of the atmosphere.
- Gaseous exchange between living organisms and atmosphere involves oxygen to a very large extent.
Answer:
It's most likely CAH102, if not i'm sorry
Explanation:
Vi = 0m/s
A = 99m/
Vf = 445m/s
T = 4.5s
D = ?
D = Vi(t) + 1/2(a)(t²)
D = 0m/s ( 4.5s) + 1/2(99m/s²)(4.5s)²
D = 1002 m
D = 1 x 10³ m