Answer:s=0.68 m
Explanation:
Given
Inclination
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using
Final velocity v=0
s=0.68 m
You've always wondered about the acceleration of the elevators in the 101-story-tall Empire State Building. One day, while visit
1 answer:
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Answer:
0.2932 rad/s
Explanation:
r = Radius = 2 m
= Initial angular momentum =
= Initial angular velocity = 14 rev/min
= Final angular momentum
= Final angular velocity
Here the angular momentum of the system is conserved
The final angular velocity is 0.2932 rad/s
Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by
where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find: