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4 years ago

To test the performance of its tires, a car

Physics

1 answer:

yarga [219]4 years ago

5 0

Answer:

0.43

Explanation:

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:

ac = v² / r

ac = (35 m/s)² / 564 m

ac = 2.17 m/s²

The total acceleration is:

a = √(ac² + at²)

a = √((2.17 m/s²)² + (3.62 m/s²)²)

a = 4.22 m/s²

Sum of forces:

∑F = ma

Nμ = ma

mgμ = ma

μ = a / g

μ = 4.22 m/s² / 9.8 m/s²

μ = 0.43

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Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are

eduard

a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. The package moves 1.8 m

d. The package's acceleration is 0 m/s²

<h3>a. The horizontal forces</h3>

The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a

Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.

Also, a frictional force also acts to oppose the motion of the package.

Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.

Let

F = push force and
f = frictional force

So, F - f = 0

F = f

= 150 N

So, the frictional force is 150 N and opposite to the push.

So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

<h3>b Vertical forces on package</h3>

The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.

The direction of the weight is downwards while the direction of the normal force is upwards.

Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.

Let W = weight of package = mg where
m = mass of package = 50 kg and
g = acceleration due to gravity = 9.8 m/s² and
N = normal force

So, the net force N - W = 0

N = W

= mg

= 50 kg × 9.8 m/s²

= 490 N

So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

<h3>c. Distance package moves</h3>

The package moves 1.8 m

Since distance, d = vt where

v = velocity = 0.6 m/s and
t = time = 3 s

So, d = vt

= 0.6 m/s × 3 s

= 1.8 m

So, the package moves 1.8 m

<h3>d. The package's acceleration</h3>

The package's acceleration is 0 m/s²

Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where

m = mass of package and
a = acceleration of package

Since F = 0,

ma = 0

a = 0

So, the package's acceleration is 0 m/s²

Learn more about force here:

brainly.com/question/25239010

6 0

3 years ago

Suppose that the resistance between the walls of a biological cell is 4.2 × 109 Ω. (a) What is the current when the potential di

Lady_Fox [76]

Answer:

(a) Current will be $17.857\times 10^{-12}A$

(b) Number of ions will be $8.258\times 10^6$

Explanation:

We have given that resistance of the biological cell $R=4.2\times 10^9ohm$

(a) We have given potential difference of 75 mV

So $V=75\times 10^{-3}volt$

From ohm's law we know that current is given by

$i=\frac{V}{R}=\frac{75\times 10^{-3}}{4.2\times 10^9}=17.857\times 10^{-12}A$

(b) We have given time t = 0.74 sec

We have to find the charge

We know that charge is given by Q = it, here i is current and t is time

So charge will be $Q=17.857\times 10^{-12}\times 0.74=13.214\times 10^{-12}C$

So number of ions will be $n=\frac{13.214\times 10^{-12}}{1.6\times 10^{-19}}=8.258\times 10^6$

6 0

4 years ago

PLEASE HELP ME WITH THSES QUESTIONS 3 SENTENCES PLEASE I BEG YOU!

JulsSmile [24]

Question 2 is because the passengers have inertia, which is a tendency to resist change in motion

6 0

4 years ago

the atomic number of uranium-235 is 92, its half-life is 704 million years, and the radioactive decay of 1 kg of 235u releases 6

wel

The overall efficiency of the conversion is 6.93%.

<h3>What is the overall efficiency?</h3>

We know that generation of electricity from radioactive fuels is one of the major ways by which we can generate electricity in many countries. Now the efficiency of each of the steps have been shown in the question;

Conversion efficiency = 35%
Transmission efficiency = 90%
Light efficiency = 22%

Overall efficiency = (0.35 * 0.90 * 0.22) * 100 = 6.93%

The energy is obtained from;

6.7X10^13 J * 6.93/100

= 4.6 * 10^12 J

Learn more about nuclear energy:brainly.com/question/12793906

#SPJ4

Missing parts;

The atomic number of uranium-235 is 92, its half-life is 704 million years and the radioactive decay of l kg of 235U releases 6.7X10^13 J. Generally, radioactive material is considered safe after 10 half-lives.

Assume that a nuclear powerplant can convert energy from 235U into electricity with an efficiency of 35%, the electrical transmission lines operate at 90% efficiency, and flourescent lights operate at 22% efficiency.

1.) What is the overall efficiency of converting the energy of 235U into flourescent light?

2.) How much energy from 1 kg of 235U is converted into flourescent light?

7 0

2 years ago

I just... I don't know man I suck at physics :(

lys-0071 [83]

Answer:

Explanation:

The velocity is 340, but the distance is not. Here's how you do this:

You need to find out the velocity of the that sound in that temp which has a formula of

v = 331.5 + .606T where T is the temp in Celcius. Filling in and using the correct number of sig dig:

v = 331.5 + .606(20) and

v = 331.5 + 10 and

v = 340 m/s. Now we need to use that in d = vt:

d = 340(2.00) so

d = 680 m

3 0

3 years ago

Read 2 more answers