Question

An exhaled air bubble underwater at 290.

Answer 1

The answer for the following problem is mentioned below.

• Therefore the final volume of the gas is 52.7 ml.

Explanation:

Given:

Initial pressure ($P_{1}$) = 290 kPa

Final pressure ($P_{2}$) = 104 kPa

Initial volume ($V_{1}$) = 18.9 ml

To find:

Final volume ($V_{2}$)

We know;

From the ideal gas equation;

    P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of gas

n represents the no of the moles

R represents the universal gas constant

T represents the temperature of the gas

So;

   P × V = constant

   P ∝ $\frac{1}{V}$

From the above equation;

              $\frac{P_{1} }{P_{2} } = \frac{V_{2} }{V_{1} }$

$P_{1}$ represents the initial pressure of the gas

$P_{2}$ represents the final pressure of the gas

$V_{1}$ represents the initial volume of the gas

$V_{2}$ represents the final volume of the gas

Substituting the values of the above equation;

                    $\frac{290}{104}$ = $\frac{V_{2} }{18.9}$

             $V_{2}$ = 52.7 ml

Therefore the final volume of the gas is 52.7 ml.