Answer:
released if the laser is used 0.056 s during the surgery
Explanation:
First, you have to calculate the energy of each photon according to Einstein's theoty, given by:

Where
is the wavelength,
is the Planck's constant and
is the speed of light
-> Planck's constant
-> Speed of light
So, replacing in the equation:

Then, the energy of each released photon by the laser is:
After, you do the inverse of the energy per phothon and as a result, you will have the number of photons in a Joule of energy:
The power of the laser is 1.1 W, or 1.1 J/s, that means that you can calculate how many photons the laser realease every second:

And by doing a simple rule of three, if
are released every second, then in 0.056 s:
are released during the surgery