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Mama L [17]
3 years ago
9

The label has been scratched off a tuning fork and you need to know its frequency. From its size, you suspect that it is somewhe

re around 250 Hz. You find a 250-Hz tuning fork and a 270-Hz tuning fork. When you strike the 250-Hz fork and the fork of unknown frequency, a beat frequency of 5 Hz is produced. When you strike the unknown with the 270-Hz fork, the beat frequency is 15 Hz. What is the unknown frequency? O 275 Hz O There is not enough information O 255 Hz O 265 Hz O 245 Hz
Physics
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

255 Hz

Explanation:

The beat frequency is the difference in frequency between two frequencies that are close.

Let the the unknown frequency be f.

Sounded with the 250 Hz tuning fork,

|250-f|=5

f = 255 \text{ or } 245

Sounded with the 270 Hz tuning fork,

|270-f|=15

f = 255 \text{ or } 285

The common value of f in both situations is 255 Hz.

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Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 20.6\; {\rm m\cdot s^{-1}} (upwards,) the vertical velocity right before landing would be (-20.6\; {\rm m\cdot s^{-1}}) (downwards.) The change in vertical velocity is:

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Hence, this projectile would be in the air for approximately 4.2\; {\rm s}.

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