The specific heat of the substance will be 0.129 J/g°C.
<h3>What is specific heat capacity?</h3>
The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
The given data in the problem is;
Q is the amount of energy necessary to raise the temperature = 3,000.0 j
M is the mass= 0.465 kg.
Δt is the time it takes to raise the temperature.=50°c
s stands for specific heat capacity=?
Mathematically specific heat capacity is given by;
Hence the specific heat of the substance will be 0.129 J/g°C.
To learn more about the specific heat capacity refer to the link brainly.com/question/2530523
Answer:
a) The minimum thickness of the oil slick at the spot is 313 nm
b) the minimum thickness be now will be 125 nm
Explanation:
Given the data in the question;
a) The index of refraction of the oil is 1.20. What is the minimum thickness of the oil slick at that spot?
t
= λ/2n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.20
we substitute
t = 750 / 2(1.20)
t = 750 / 2.4
t = 312.5 ≈ 313 nm
Therefore, The minimum thickness of the oil slick at the spot is 313 nm
b)
Suppose the oil had an index of refraction of 1.50. What would the minimum thickness be now?
minimum thickness of the oil slick at the spot will be;
t = λ/4n
given that; wavelength λ = 750 nm and index of refraction of the oil n = 1.50
we substitute
t = 750 / 4(1.50)
t = 750 / 6
t = 125 nm
Therefore, the minimum thickness be now will be 125 nm
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2
So, option B is your answer!
Hope this helps!
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Explanation: HOPE THIS HELPSS!! ;))
