While discussing the testing of a Hall-effect switch:
1 answer:
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Answer:
See explanation
Explanation:
//Include the
//required header files.
#include <stdio.h>
//Define the
//main() function.
int main(void) {
//Declare the
//required variables.
char input_char;
int input_int;
double input_double;
char input_string[100];
//Prompt the user
//to enter an integer.
printf("Enter integer: ");
//Read and store
//the integer.
scanf("%d", &input_int);
//Prompt the user
//to enter a double value.
printf("Enter double: ");
//Read and store
//the double value.
scanf("%lf", &input_double);
//Prompt the user
//to enter a character.
printf("Enter character: ");
//Read and store
//the character.
scanf(" %c", &input_char);
//Prompt user to
//enter the string
printf("Enter string: ");
//Read and
//store the string.
scanf("%s", input_string);
//(1)
//Display the values.
printf("%d %lf %c %s\n",
input_int, input_double,
input_char, input_string);
//(2)
//Display the values
//in reverse order.
printf("%s %c %lf %d\n",
input_string, input_char,
input_double, input_int);
//(3)
//Cast the double to
//an integer and display it.
printf("%lf cast to an integer is %d",
input_double, (int)(input_double));
//Return from the
//main() function.
return 0;
}
Answer:
critical clearing angle = 70.3°
Explanation:
Generator operating at = 50 Hz
power delivered = 1 pu
power transferable when there is a fault = 0.5 pu
power transferable before there is a fault = 2.0 pu
power transferable after fault clearance = 1.5 pu
using equal area criterion to determine the critical clearing angle
Attached is the power angle curve diagram and the remaining part of the solution.
The power angle curve is given as
= Pmax sinβ
therefore : 2sinβo = Pm
2sinβo = 1
sinβo = 0.5 pu
βo = ⁰
also ; 1.5sinβ1 = 1
sinβ1 = 1/1.5
β1 = = 41.81⁰
∴ βmax = 180 - 41.81 = 138.19⁰
attached is the remaining solution
The critical clearing angle = ≈ 70.3⁰
