Answer:
Under the normal sign convention, the distributed load on a beam is equal to the: O The second derivative of the bending moment with respect to the length of the beam O Negative of the rate of change of the shear force with respect to the length of the beam.
Sorry if the answer is wrong
Complete Question:
CMOS Logic
As you discovered in lab last week, the advantage of CMOS logic is that no drain current flows through the MOSFETs when the output is either high or low. Because the CMOS logic family is based on the inverter, the logic functions of NOT, NAND, and NOR are easy to create. The logic functions AND and OR, however, require us to build a NAND or NOR gate and then add an inverter to the gate output: AND = NAND+NOT
<em>Design a 2-input CMOS OR-gate using MOSFETs . Make certain that the power dissipation is zero when the output is both logic 1 and logic 0 . Add NOT logic to one of switches to the inputs of the OR gate .</em>
Answer and Explanation:
- The question require you to design a 2 input CMOS
- make certain that the power dissipation is zero when the output is both logic 1 and logic 0
- Add NOT logic to one of the switches to the input of the OR gate
attached below is a diagram of the designed 2-input CMOS labelled with all the other features explicitly stated
Answer:
1.) 2.4
2.) 112 lbs
3.) 7.85 inches
4.) 6 lbs
5.) 2 lbs
6.) 67%
Explanation:
Given that
Radius of the wheel R = 1 foot
1 foot = 12 inches.
Radius of the axle r = 5 inches
1.) The mechanical advantage MA is :
MA = R/r = 12/5 = 2.4
2.) How much resistance force can ideally be overcome when an effort of 80 lbs is applied to the wheel of the water valve in problem 1?
MA = Load / effort
Where effort = 80 lbs
Substitute MA and effort into the formula
2.4 = Load / 80
Cross multiply
Load = 2.4 × 80 = 192 lbs
The resistance force to be overcome will be
Force = load - effort
Resistance force = 192 - 80 = 112 lbs
3) What is the linear distance traveled when a 2.5' diameter wheel makes one revolution
One revolution = 2π
Radius = 2.5 /2 = 1.25 inches
Linear distance S = angular distance Ø × radius r
S = Ør
S = 2π × 1.25
S = 7.85 inches
4. ) given that
Wheel radius R = 4
Axle radius r = 1
MA = 4/1 = 4
MA = Load / effort
4 = 24/ effort
Effort = 24/4 = 6 lbs
5.) 6 - 4 = 2lb
6.) Efficiency = MA / VR × 100
Efficiency = 4 / 6 × 100
Efficiency = 67%
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Answer:
#WeirdestQuestionOfAllTime
Explanation: