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Georgia [21]
3 years ago
6

Can anyone give me the formula to Carbon dioxide please?

Chemistry
1 answer:
kifflom [539]3 years ago
8 0
Co2 is the fornula to carbon dioxide
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Give the hybridization for the c in hcch. group of answer choices
Tamiku [17]

The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.

Discussion:

There are three different forms of hybridization -

  1. sp- The first occurs when two carbon atoms are triple linked.
  2. sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
  3. sp₃- When a single bond joins two carbon atoms, this is known as sp₃.

In the case of acetylene(HCCH or C₂H₂):

  • The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
  • As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.

                                              H-C≡C-H

Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.

Learn more about hybridization here:

brainly.com/question/14140731

#SPJ4

5 0
2 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
3 years ago
When trying to clean muddy, dirty river water, which method would work
Llana [10]
When trying to clean muddy, dirty river water, FILTRATION would work best
6 0
3 years ago
6.25 g of HCl(g), a strong acid, is dissolved in water to make a 280-ml solution.
elena-14-01-66 [18.8K]

pH= -log[0,611]= 0,21

7 0
3 years ago
An element is:
SIZIF [17.4K]
C. A pure chemical substance consisting of one type of atom
3 0
3 years ago
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