1) Frequency: 
the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

The energy of a photon is given by

where
is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

2) Wavelength: 91.2 nm
The wavelength of the photon can be found from its frequency, by using the following relationship:

where
is the speed of light and f is the frequency. Substituting the frequency, we find

Explanation:
We have,
Semimajor axis is 
It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

G is universal gravitational constant
M is solar mass
Plugging all the values,

Since,

So, the orbital period of a dwarf planet is 138.52 years.
I literally looked everywhere for the answer, and I still found nothing. I hope you get it right. Sorry.
The x and y components of the velocity vector is 17.32 m/s and 10 m/s respectively.
<h3>
What is the x - component of the velocity?</h3>
The x-component of the ball's velocity is the velocity of the ball in the horizontal direction or x-axis.
The velocity of the ball in x-direction is calculated as follows;
Vx = V cosθ
where;
- Vx is the horizontal velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vx = (20 m/s) x (cos 30)
Vx = 17.32 m/s
The velocity of the ball in y-direction is calculated as follows;
Vy = V sinθ
where;
- Vy is the vertical velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vy = 20 m/s x sin(30)
Vy = 10 m/s
Learn more about x and y components of velocity here: brainly.com/question/18090230
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