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Natali5045456 [20]
3 years ago
13

Brainliest for whoever is first and right.

Physics
1 answer:
devlian [24]3 years ago
3 0

The answer is 9.8, did this last year in AP Science

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A radioactive particle has a half life of 1 second. If it moves at 3/5 the speed of light, from my point of view standing still
AVprozaik [17]

The half-life observed by an observer at rest is 1.25 s

Explanation:

In this problem, the particle is travelling at a significant fraction of the speed of light: therefore, we have to consider the phenomenon of the time dilation. The half-life of the particle as measured by an observer at rest is given by

T=\frac{T_0}{\sqrt{1-(\frac{v}{c})^2}}

where

T_0 is the proper half-life of the particle

v is the speed of the particle

c is the speed of light

For the particle in this problem,

T_0 = 1 s

v=\frac{3}{5}c=0.6 c

Substituting into the equation, we find:

T=\frac{1}{\sqrt{1-(\frac{0.6c}{c})^2}}=1.25 s

#LearnwithBrainly

7 0
3 years ago
Over due by alot please help
ira [324]

Answer:

i would say the third one

Explanation:

may i be brainliest?

5 0
3 years ago
A continuous length of wire is made into 10 coaxial loops, located in the plane of this page. Each loop has a cross sectional ar
AleksandrR [38]

Answer:

e = 10 V

Explanation:

given,

number of the coaxial loops = 10

Cross sectional area =  0.5 m²

magnitude of magnetic field =

B = 3 T + (2 T/s)*t.

B = ( 3+ 2 t ) T

induced potential difference = ?

At time = 2 s

we know,

induced emf

e = - N\dfrac{d\phi}{dt}

∅ = B . A

e = - N\dfrac{d(BA)}{dt}

e = - NA\dfrac{dB}{dt}

e = - 10 \times 0.5 \times \dfrac{d}{dt}(3 + 2 t)

e = - 10 \times 0.5 \times 2

e = -10 V

magnitude of induced emf

|e| = |-10 V|

e = 10 V

the induced potential difference in the loop = e = 10 V

7 0
3 years ago
Which of the following absorbs the MOST heat energy?
goldfiish [28.3K]
Darker is warmer C. Black objects.
5 0
3 years ago
Read 2 more answers
7 questions, lots of points, please answer as many as possible.
maw [93]
4. gravitational
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4 years ago
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