a) Mass of gasiline = 18.9 kg; b) distance travelled = 204 mi
a) <em>Mass of gasoline
</em>
<em>Step 1</em>. Convert <em>$CDN to $US</em>
$US = $30.00 CDN × (0.942$US/$1 CDN) = $28.26 US
<em>Step 2</em>. Calculate the <em>volume of gasoline
</em>
V = $28.26 US × (1 gal gasoline/$3.82 US) = 7.399 gal
<em>Step 3</em>. Convert <em>gallons to litres
</em>
V =7.399 gal × (3.785 L/1 gal) = 28.00 L
<em>Step 4</em>. Calculate the <em>mass of the gasoline
</em>
Mass = 28 000 mL × (0.674 g/1 mL) = 18 900 g = 18.9 kg
<em>
b) Distance travelled
</em>
<em>Step 1</em>. Calculate the <em>kilometres</em>
Kilometres = 28.00 L × (100 km/8.53 L) = 328.3 km
<em>Step 2</em>. Convert <em>kilometres to miles</em>
Miles = 328.3 km × (1 mi/1.609 km) = <em>204 mi</em>
Answer:
As we move from left to right in periodic table atomic radii decreases.
Explanation:
Along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. Thus the attraction of the atoms for valance electrons increases. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required, and electronegativity increases.
Along group:
As we move from top to bottom in periodic table the atomic sizes increases.The electrons are added in next energy level in every next element. Thus the valance electrons farther away from the nucleus and hold of nucleus becomes weaker, because of weak nuclear attraction atomic radii increases.The ionization energy decreases.
The equilibrium constant of reaction, usually denoted as K, is a unit of ratio. The ratio involves concentrations or partial pressures of products to reactants. But you also have to incorporate their stoichiometric coefficients in the reaction as their respective exponents. If K is in terms of concentration, only the substances in their aqueous state are the ones that are included only in the expression. If K is in terms of partial pressures, only the substances in gaseous states are the ones that are included only in the expression. For this problem, it would be in terms of partial pressures. To properly show you how it's done, consider this equilibrium reaction:
aA (g) + bB (g) ⇆ nN (g)
The equilibrium constant for this reaction is:
K = [N]ⁿ/[A]ᵃ[B]ᵇ
where the [] brackets denotes partial pressures of the substances
Particularly, for the reaction <span>a(g)⇌b(g), the K expression would be
</span>K = [B]/[A]
So, if K is less than one, that means that the numerator is less than the denominator. It follows that the partial pressure of reactant A is greater than product B. Since A is greater, then the more favorable direction would be the forward reaction. The δG°rxn would then be negative in value. So δG°rxn < 0.
To explain, δG°rxn is a criterion for spontaneity. If δG°rxn is negative, the reaction is spontaneous. If δG°rxn is positive, it is non-spontaneous. Since the favorable reaction is the forward reaction, it is spontaneous.
Answer:
ExplanaPulpotomy is a vital pulp therapy in which the coronal portion of the pulp is removed surgically and the remaining radicular pulp is preserved intact. Over the remaining radicular pulp tissue, a suitable material is placed which has the potential to protect the pulp from further insult and initiate healing and repairtion: