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LenaWriter [7]
3 years ago
6

2. Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute..

. The water is the solution, and carbon dioxide is the solvent.. . The carbon dioxide is the solution, and the water is the solvent.. . The water is the solvent, and the carbon dioxide is the solute.. . . 3. For the reaction CH3COOH CH3COO + H+, which of the following statements is true?. . CH3COO is an Arrhenius base.. . CH3COO is a Lewis base.. . CH3COOH is a Brønsted-Lowry acid.. . CH3COOH is a Brønsted
Chemistry
2 answers:
Flura [38]3 years ago
7 0

Answer: 2. The water is the solvent, and the carbon dioxide is the solute.

3. CH_3COOH] is a Brønsted-Lowry acid.

Explanation:

2. Solute is the dispersed phase of the solution and is present in small quantities whereas solvent is the dispersion medium and is present in large proportions. carbonated drinks contain carbon dioxide dissolved in water and thus carbon dioxide is the solute and water is the solvent which together form a solution.

3. Bronsted lowry acid  is a substance which donates H^+. Bronsted lowry base is a substance which accepts H^+.

Arrhenius acid is a substance which donates H^+ when dissolved in water.Arrhenius base is a substance which donates OH^- when dissolved in water.

Lewis acid  is a substance which accepts electrons. Lewis base is a substance which donates electrons.

CH_3COOH\rightarrow CH_3COO+H^+

Thus as acetic acid donates  H^+ , it is considered as  Bronsted-Lowry acid.


const2013 [10]3 years ago
3 0
A carbonated soft drink hs a large amount of water dissolved with ample amount of carbon dioxide. In this case, the solvent is water and carbon dioxide is the solute. In 2, for the reaction <span>CH3COOH = CH3COO + H+, CH3COOH is a Bronsted-Lowry acid because it releases a proton which is H+. </span>
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Pete Gannett

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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y

Seems to be an ideal gas law question. The relevant equation is:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.

To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.

n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles

So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:

# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules

Note, it does not matter what the gas is.

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