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LenaWriter [7]
3 years ago
6

2. Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute..

. The water is the solution, and carbon dioxide is the solvent.. . The carbon dioxide is the solution, and the water is the solvent.. . The water is the solvent, and the carbon dioxide is the solute.. . . 3. For the reaction CH3COOH CH3COO + H+, which of the following statements is true?. . CH3COO is an Arrhenius base.. . CH3COO is a Lewis base.. . CH3COOH is a Brønsted-Lowry acid.. . CH3COOH is a Brønsted
Chemistry
2 answers:
Flura [38]3 years ago
7 0

Answer: 2. The water is the solvent, and the carbon dioxide is the solute.

3. CH_3COOH] is a Brønsted-Lowry acid.

Explanation:

2. Solute is the dispersed phase of the solution and is present in small quantities whereas solvent is the dispersion medium and is present in large proportions. carbonated drinks contain carbon dioxide dissolved in water and thus carbon dioxide is the solute and water is the solvent which together form a solution.

3. Bronsted lowry acid  is a substance which donates H^+. Bronsted lowry base is a substance which accepts H^+.

Arrhenius acid is a substance which donates H^+ when dissolved in water.Arrhenius base is a substance which donates OH^- when dissolved in water.

Lewis acid  is a substance which accepts electrons. Lewis base is a substance which donates electrons.

CH_3COOH\rightarrow CH_3COO+H^+

Thus as acetic acid donates  H^+ , it is considered as  Bronsted-Lowry acid.


const2013 [10]3 years ago
3 0
A carbonated soft drink hs a large amount of water dissolved with ample amount of carbon dioxide. In this case, the solvent is water and carbon dioxide is the solute. In 2, for the reaction <span>CH3COOH = CH3COO + H+, CH3COOH is a Bronsted-Lowry acid because it releases a proton which is H+. </span>
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1. A(n)______________ bond forms when one atom gives up one or more electrons to another atom.
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A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál
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\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

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