Answer:
The ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m
Explanation:
Fringe spacing w = λ·D/s
Diffraction grating, d·sin(θ) = n·λ
n = Number of lines
When θ = 90°, we have, sin(θ) = sin(90°) = 1
Therefore;
d·sin(θ) = d × 1 = d = n·λ
When n = 6 lines and d = 550-nm, we have;
d = 6 × 550-nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
Therefore, the ruling separation must be between 2.2 × 10⁻⁶ m and 3.3 × 10⁻⁶ m.
Answer:
Explanation:
given that
mass = 10kg
distance = 4m
force = 50N
to calculate the workdone when the force is applied in the same direction of displacement
mathematically,
workdone = force × distance
Workdone = 50 × 4
workdone = 200 joules
2) to calculate the workdone at an angle of 30° with the displacement we apply the formula
workdone = force × distance × cos Ф
workdone = 50 × 4 × cos 30°
workdone = 200 × 0.866
workdone = 173 . 2 joules
Answer:
C) 64lb
Explanation:
use the linearity method to find the weight of nadir on another planet, it is applied as follows.
Nadir Weight in earth ⇒ Nadir weight in another planet
Vince Weigh in eart ⇒ X
our goal is to find the weight of vince in another planet (X), for this we multiply the diagonal that continents the data and divide among the remaining
140pounds ⇒ 56lb
160pounds ⇒ X
X=
Vince weigh on the other planet is C) 64lb
S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)
S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m
Distance double 720m*2=1440m
V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
