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asambeis [7]
3 years ago
10

What is the term for removing refrigerant in any condition from a system and storing it in an external container without necessa

rily testing for processing it in any way
Engineering
1 answer:
Vlad [161]3 years ago
8 0

Answer:

The term you are looking for is recovery. The process of recovering refrigerant is to remove some or all the refrigerants of a system and deposit it in an external storing for further processing or storage. This recovered refrigerant won´t be used again in the system in any near time period.

If the refrigerant is removed to be instantly processed and cleaned to be reutilized in the same system, this action is known as recycling.

You might be interested in
A direct-coupled amplifier has a low-frequency gain of 40 dB, poles at 2 MHz and 20 MHz, a zero on the negative real axis at 200
rewona [7]

Answer:

Explanation:

Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz

Zero at -200MHz, zero at infinity.

A) A(s) = 100FH(s)

B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz

              (2): 2pi × 20 × 10^6= 4pi × 10^6 MHz

 Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.

T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)

8 0
3 years ago
A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and
Morgarella [4.7K]

Answer:

shrinkage ratio  = 1.538

Explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³  = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝  \frac{1}{volume}  

so \frac{\gamma d}{\gamma 'd}  = \frac{v'}{v}

\frac{82}{96}  = \frac{1350000}{v}

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio = \frac{96}{62.4}  

shrinkage ratio  = 1.538

6 0
3 years ago
(c) As Engineering and Computing students, you must be familiar, with the respective professional bodies, as well as, Rules of P
guajiro [1.7K]

The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
  • They will  Avoid harm.
  • Be honest and trustworthy.
  • They will be fair and take action that do to discriminate others.

<h3>What are the Characteristics of Code of Ethics?</h3>

The code of ethics are known to be a kind of a universal moral values, that is one that state that what a person expect of any given employee such as been trustworthy, respectful, responsible, and others.

Note that Rules of Practice, Professional Obligations and Codes of Ethics. are known to be put in place to avoid issues that may lead to conflict.

Therefore, i believe that  As Engineering and Computing students, the respective professional bodies, Rules of Practice, Professional Obligations and Codes of Ethics are good and acts as a check and balance to us.

Therefore, The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
  • They will  Avoid harm.
  • Be honest and trustworthy.
  • They will be fair and take action that do to discriminate others.

Learn more about Engineering rules from

brainly.com/question/17169621

#SPJ1

4 0
2 years ago
When replacing a timing belt, many experts and vehicle manufacturers recommend that all of the following should be replaced exce
lora16 [44]

Answer:

Correct Answer:

A. water pump

Explanation:

<em>Timing belt in a vehicle helps to ensure that crankshaft, pistons and valves operate together in proper sequence.</em> Timing belts are lighter, quieter and more efficient than chains that was previously used in vehicles.

<em>Most car manufacturers recommended that, when replacing timing belt, tension assembly, water pump, camshaft oil seal should also be replaced with it at same time. </em>

7 0
3 years ago
(a) Aluminum foil used for storing food weighs about 0.3 grams per square inch. How many atoms of aluminum are contained in one
atroni [7]

Answer:

note:

solution is attached due to error in mathematical equation. please find the attachment

3 0
3 years ago
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