Answer:
Kim kim kim kim kim ath marath enthe kantha
Explanation:
Ninn chumbenem enne thellerthii.
Nin vadabell enne shwasichu!
Im pretty sure the answer is c
Answer:-
Option 2
Explanation:-
In a multi step reaction, the overall reaction is as fast as the slowest step only.
So the rate of a multistep reaction is the same as the rate of its slowest step.
The gas phase reaction was found to be second order wrt NO2.
So the slowest step must have 2 NO2 since the dependence is second order on NO2.
It was also found to be zero order wrt CO.
So the slowest step must not contain any CO since it’s presence has no effect on the reaction (zero order).
Among all options, only number 2 meets the two criterion
Thus the steps are
NO2 + NO2 – NO3 + NO (Slow)
NO3 + CO – NO2 + CO2 (Fast)
The formula unit equation for the given reaction occurring in water is
CaS(aq) + FeBr₂(s) → FeS(s) + CaBr₂(aq).
<h3>What is chemical reaction?</h3>
Chemical reactions are those reaction in which reactant molecules react with each other for the formation of product.
When calcium sulfide reacts with iron (II) bromide for the formation of iron(II) sulfide and calcium bromide will be represented through the following equation:
CaS(aq) + FeBr₂(s) → FeS(s) + CaBr₂(aq)
Above reaction best explains the formula unit of given reaction as all valency of atoms are satisfied there.
Hence, the required formula unit is CaS(aq) + FeBr₂(s) → FeS(s) + CaBr₂(aq).
To know more about chemical reactions, visit the below link:
brainly.com/question/26018275
#SPJ1
Answer:
final volume = 10.5 Liters N₂(g) at 21°C and 823Torr*
Explanation:
*Note=>No specified mass value of N₂(g) is defined in the problem. Therefore for a starting point, the gas sample is assumed to be 1.00 mole N₂(g) at STP conditions 22.4L
Determine volume of N₂(g) at 21°C(=294K) and 823 Torr (= 2.286 Atm).
Start with Volume of N₂(g) at 0°C and 1 Atm pressure => 22.4L and adjust to final volume of N₂(g) based upon 21°C(=294K) and 823 Torr (= 2.286 Atm).
V(final) = 22.4L(294K/273K)(360 Torr/823 Torr) = 22.4L(294/273)(360/823) = 10.55 Liters final volume.
Note: The volume of 1 mole (assumed) of any gas at STP (0°C/1 Atm) is 22.4 Liters. To convert to non-STP conditions, convert temperature and pressure factors (changes) that reflect what happens when the gas is expanded or decreased; but, these adjustments are taken independently for each variable of interest. The following notes explain.
For the increase in temperature from 0°C(=273K) to 21°C(=294K) one must apply a temperature ratio that will increase volume. That is, the change in volume due to the temperature change is 294K/273K. If a 273K/294K ratio were used the volume would have decreased. Not so for heating a sample of gas.
For the increase in pressure one should expect a decrease in volume. Therefore apply a pressure ration that will effectively decrease the volume of the gas. That is, to decrease a 22.4L sample at STP multiply the standard volume by a ratio of pressures that will decrease 22.4L to a smaller volume. That is, V(final by pressure effects) multiply by 360Torr/823Torr to decrease the STP VOLUME (22.4L) to the new non-standard volume. If 823Torr/360Torr were used, the final volume would not be smaller, but larger. Such is the physical effect of an increasing pressure change.
