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PolarNik [594]
3 years ago
9

Two objects having masses m1 and m2 are connected to each other as shown in the figure and are released from rest. There is no f

riction on the table surface or in the pulley. The masses of the pulley and the string connecting the objects are completely negligible. What must be true about the tension t in the string just after the objects are released?

Physics
2 answers:
GrogVix [38]3 years ago
5 0

Answer:

T<m2hh

Explanation:

Two objects having masses m1 and m2 are connected to each other as shown in the figure and are released from rest. There is no friction on the table surface or in the pulley. The masses of the pulley and the string connecting the objects are completely negligible. What must be true about the tension t in the string just after the objects are released?

Two masses  m1 and m2  is released and there is tension T in the string

a is the acceleration of the system

Therefore

For m1

T-m1g=m1a

T=m1(g+a)

m2

this is so because te weight is going downward wile tension in te rope is facing upward

m2g-T=m2a

T=m2(g-a)

from the equation ,

T<m2

tankabanditka [31]3 years ago
4 0

Answer:m_1g

Explanation:

Given

Two masses m_1  and m_2  is released and there is tension T in the string

Suppose a is the acceleration of the system

Therefore from Diagram

For m_1

T-m_1g=m_1a

T=m_1(g+a)------1

for m_2 body

m_2g-T=m_2a

T=m_2(g-a)-------2

From above two Equation it is said that Tension is greater than m_1g and less than m_2g

m_1g

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A string is attached to a ball that has a mass of 0.11 kg. A student pulls up on the string so that the ball accelerates upward
enot [183]

Answer:

T=+1.133N

Explanation:

Tension and weight are forces that have opposite directions

Weight is negative (downward)

W=m*g= 0.11kg*(-9.8m/s^2)

W= -1.078N

Tension is possitive (upward)

The total force will be the sum of both (the difference taking in consideration the direction)

Ft= T+W

Also the total force is the product of the mass due to acceleration:

Ft=m*a

Ft= +0.11kg*0.5m/s^2

Ft=+0.055N (upward)

Tension will be the difference between Ft and W:

T= Ft-W

T=+0.055N-(-1.078N)

T=+1.133N

7 0
3 years ago
A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i
andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

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at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) =  337.93

note : w = \sqrt{k/m}   = \sqrt{337.93} = 18.38 rad/sec

Period of oscillation =  2\pi  / w

                                  = 0.34 sec

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Why does sound travel faster in water than in air?
mars1129 [50]

Answer:

C.

Explanation:

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The iron nail’s mass is 16 grams and its temperature drops 650 C when dropped into the water. How much heat energy did the iron
Mice21 [21]

The heat energy transferred by the iron nail is 4680 J

Explanation:

The thermal energy transferred by a substance to another substance is given by the equation

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is its change in temperature

For the iron nail in this problem, we have:

m = 16 g

C=0.450 J/g^{\circ}C

\Delta T = -650^{\circ}C

So, the amount of heat energy given off by the nail is

Q=(16)(0.450)(-650)=-4680 J

where the negative sign indicates that the heat is given off.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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3 years ago
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