A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of
the stone if it hit the plane a distance L down the slope from the point of launch?
1 answer:
Answer:
S = V t where S is the horizontal distance traveled
1/2 g t^2 = H where H is the vertical distance traveled
t^2 = 2 H / g
V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations
tan theta = H / S
V^2 = S g / (2 tan theta)
Using S = L cos theta
V^2 = L g cos theta / (2 tan theta)
Giving V in terms of L and theta
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