<span>The radio frequency characteristic that best determines the range of a 2.4 GHz ism signal is the wavelength.
This frequency can be used in WiFi and can reach up to 46 meters when indoors and about 92 meters when outdoors.
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Answer:
That is, mechanical waves cannot travel through a vacuum. This feature of mechanical waves is often demonstrated in a Physics class. A ringing bell is placed in a jar and air inside the jar is evacuated. Once air is removed from the jar, the sound of the ringing bell can no longer be heard.
<h3><u>Answer;</u></h3>
<em>Electric motor</em>
<h3><u>Explanation;</u></h3>
- <em><u>Energy</u></em> is the ability to do work. According to the law of conservation of energy,<em><u> energy can not be created nor destroyed but can be changed from one form to another</u></em>.
- Changing energy from one form to another is done by devices we call <em><u>transducers. These are elements that convert energy from one form to another.</u></em>
- In this case, electrical motor is an example of a transducer that converts electrical energy to kinetic energy. <em><u>Electrical energy is supplied to a the motor which converts it to rotational energy or mechanical energy then to kinetic energy.</u></em>
Becuz when you wash up in the tub you want layers of soap so you don’t stink
Answer:
a,)3.042s
b)4.173s
c)3.281s
Explanation:
For a some pendulum the period in seconds T can be calculated using below formula
T=2π√(L/G)
Where L = length of pendulum in meters
G = gravitational acceleration = 9.8 m/s²
Then we are told to calculate
(a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 3.00 m/s2?
Since oscillations for this pendulum is located in the elevator that is accelerating upward at 3.00 then
use G = 9.8 + 3.0 = 12.8 m/s²
Period T=2π√(L/G)
T= 2π√(3/12.8)
T=3.042s
b) (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 3.00 m/s2?
G = 9.8 – 3.0 = 6.8 m/s²
T= 2π√(3/6.8)
T=4.173s
C)(c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 3.00 m/s2?
Net acceleration is
g'= √(g² + a²)
=√(9² + 3²)
Then period is
T=2π√(3/11)
T=3.281s
