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Tanya [424]
3 years ago
9

The distiction between long and short term memory

Physics
1 answer:
RUDIKE [14]3 years ago
4 0

Answer:

The main difference between short term and long term memory is that the short term memory stores data temporarily while the long term memory stores data permanently. Moreover, the short term memory is volatile while the long term memory is nonvolatile. Memory is the component in a computer that stores data and information.

Explanation:

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What is a crystal as applied in physics ​
Scilla [17]

Answer:

The correct answer is - A matter that has an ordered arrangement of atoms, molecules, or ions.

Explanation:

In physics, a crystal is a type of solid matter in which a highly arranged molecule or atoms present to form a lattice that extended in all directions. It is a lightweight clear solid which is normally is colorless.

It can be cubic, hexagonal, triclinic, monoclinic, orthorhombic, tetragonal, and trigonal that are ordered arrangments. Its internal symmetry is visible to its surface.

4 0
3 years ago
In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car​
Dima020 [189]

Answer:

2 m/s

Explanation:

3 0
3 years ago
According to the law of conservation of energy, which statement must be
Gre4nikov [31]

Answer:

D. The total energy of a system can increase only if energy enters the

system

energy must be conserved--it cannot be created or destroyed.

so, if the energy of a system increases, that energy must have come from somewhere

hope this helps!!

5 0
2 years ago
Help me please!! 15points
Romashka-Z-Leto [24]

Explanation:

Acceleration is the change in speed over change in time.

a = Δv / Δt

a. The car's acceleration is:

a = (80 km/h − 0 km/h) / 10 s

a = 8 km/h/s

So every second, the speed increases by 8 km/h.

b. The cyclist's acceleration is:

a = (16 m/s − 4.0 m/s) / 5.6 s

a = 2.1 m/s²

c. The stone's speed is:

10.0 m/s² = (v − 0 m/s) / 3.5 s

v = 35 m/s

d. The time is:

1.6 m/s² = (10 m/s − 0 m/s) / t

t = 6.3 s

4 0
4 years ago
Consider the following distribution of objects: a 5.00-kg object with its center of gravity at (0, 0) m, a 3.00-kg object at (0,
Minchanka [31]

Answer:

(-1.5,-1.5)m

Explanation:

we know that:

X_{cm} = \frac{m_1x_1+m_2x_2....m_nX_n}{m_1+m_2...m_n}

where X_{cm} is the location of the center of gravity in the axis x, m_i is the mass of the object i and x_i the first coordinate of center of gravity of object i.

so:

0 = \frac{(5kg)(0)+(3kg)(0)+(4kg)(3)+(8kg)x_4}{5kg+3kg+4kg+8kg}

Where x_4 is the first coordinate of the center of gravity for the fourth object.

Therefore, solving for x_4, we get:

x_4 = -1.5m

At the same way:

Y_{cm} = \frac{m_1y_1+m_2y_2....m_ny_n}{m_1+m_2...m_n}

where Y_{cm} is the location of the center of gravity in the axis y, m_i is the mass of the object i and y_i the second coordinate of center of gravity of object i. replacing values we get:

Y_{cm} = \frac{(5kg)(0)+(3kg)(4)+(4kg)(0)+(8kg)y_4}{5+3+4+8}

Where y_4 is the second coordinate of the center of gravity for the fourth object.

solving for y_4:

y_4 = -1.5m

It means that the object of mass 8kg have to be placed in the  

coordinates (-1.5,-1.5) m.

8 0
3 years ago
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