Answer:
When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.
Hope that helps.
Answer: B)To the left of the charges.
Explanation: between the charges the electric field will not cancel but will be added since electric field lines from both charges point in the same direction. To the right of the charge the -4q will take over as it’s strength overcomes the strength of the +q charge. At this point the magnitude of +q will never reach a magnitude strong enough to cancel the -4q. To the left, it is further away from -4q and is closer to +q and electric field lines point in different direction
Answer:
6.5454 m
Explanation:
Let the distance from the wire carrying 3 A current is x
Then the distance from the the carrying current 8 A is 24-x
We know that magnetic field due to long wire is given by
It is given that magnetic field is zero at some distance so

Here
So 
This situation describes the Hooke's Law which states that "When an elastic object - such as a spring - is stretched, the increased length is called its extension. The extension of an elastic object is directly proportional to the force applied to it". The formula is <span>F = k × e , F for the force, k for spring constant expressed in N/m, e for extension in m. This equation works for as long the spring is not stretch too much because once it exceeded its limit, the spring will not return to its original length the moment the load is removed.</span>
The complete question is;
A circular coil consists of N = 410 closely winded turns of wire and has a radius R = 0.75 m. A counterclockwise current I = 2.4 A is in the coil. The coil is set in a magnetic field of magnitude B = 1.1 T.
a. Express the magnetic dipole moment μ in terms of the number of the turns N, the current I, and radius
R.
b. Which direction does μ go?
Answer:
A) μ = 1738.87 A.m²
B) The direction of the magnetic moment will be in upward direction.
Explanation:
We are given;
The number of circular coils;
N = 410
The radius of the coil;R = 0.75m
The current in the coils; I = 2.4 A
The strength of magnetic field;
B =1.1T
The formula for magnetic dipole moment is given as;
μ = NIA
Where;
N is number of turns
I is current
A is area
Now, area; A = πr²
So, A = π(0.75)²
Thus,plugging in relevant values, the magnetic dipole moment is;
μ = 410 * 2.4 * π(0.75)²
μ = 1738.87 A.m²
B) According to Fleming's right hand rule, the direction of the magnetic moment comes out to be in upward direction.