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Burka [1]
3 years ago
10

Write an algorithm and draw a flowchart to convert the length in feet to centimeter

Engineering
1 answer:
Simora [160]3 years ago
3 0

Answer:

blah blah blah sh ut up read learn

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ngumfowethu kuphela ovunyelwe ukuphendula lo mbuzo ngakho-ke ngicela ungawuphenduli uma uwubona. Ngiyabonga :)
Irina-Kira [14]

Answer:

WHAT?

Explanation:

6 0
3 years ago
Read 2 more answers
An alloy to be used for a spring application must have a modulus resilience of at least 0.79 x 106 J/m3 (0.79 x 106 Pa). What mu
xxTIMURxx [149]

Answer:

4.13 MPa

Explanation:

Given

Modulus of elasticity = E = 102 GPa

E = 102 * 10^9

Modulus resilience U = 0.79 * 106Pa

Modulus of Resilience U = y²/2E --- Make y the subject of formula

y² = 2EU

y = √(2EU)

y = √(2 * 102 * 10^9 * 0.79 * 106)

y = √1.708296E13

y = 4133153.759540044

y = 4.13E6

y = 4.13MPa

3 0
3 years ago
Explain how does optimism and open-minded can help engineers succeed at their jobs
Aleonysh [2.5K]

Answer:There is an idea floating around that being an optimist is good for you. In her book, ‘Smile or Die’, Barbara Ehrenreich traces the origins of this idea, from early religious eccentrics to modern day psychology and motivational gurus. Related notions are that self belief is important to achievement, that confidence is needed, and you get what you expect. I freely admit that there was a time when I also thought that expectations influenced results, and sometimes they do.

However, since then I have examined this much more closely and changed my views. I now realise that there are downsides to optimism too, and that optimism and pessimism are not the only options. If you are interested in exploring this in more detail, especially if you have been uncomfortable with the self-delusion that positive thinking usually involves, then this article may provide a clearer understanding of a reasonable alternative that works and makes sense.

What is the choice?

Research has fairly consistently shown two biases in our predictions about the net benefits of actions we plan to take: (1) on average our predictions are usually too high, and (2) when asked to give ranges for our predictions our ranges tend to be too narrow.

This gives a useful insight into some familiar mental outlooks that we might try to adopt:

Pessimism: Expecting unrealistically low net benefits from courses of action (i.e. poor results achieved, if at all, after a struggle), and being unrealistically sure that those poor benefits will be achieved.

Optimism: Expecting unrealistically high net benefits from courses of action (i.e. great results easily achieved), and being unrealistically sure that those great benefits will be achieved.

Both of these involve overly narrow predictions. If we correct that by being more open-minded then other possible outlooks emerge. The one I will focus on in this article is this:

Open-minded realism: Having a view of the results of courses of action that is not biased towards high or low net benefits, and is open to a range of possibilities in a way that is, again, rational and unbiased, rather than overly narrow.

Here's a picture that shows each of these outlooks. The horizontal axis represents the outcome of some course of action, ranging from terrible on the left to great on the right. The height of the graphs represents the person's belief that each level of outcome will occur. Pessimism is narrow and negative, represented by the red distribution. Optimism is narrow and positive, represented by the green distribution. Open-minded realism, represented by the black curve, is unbiased and more spread, reflecting an open mind about what might happen.

Explanation:

3 0
2 years ago
A 225 MPa conducted in which the mean stress was 50 MPa and the stress amplitude was (a) Compute the maximum and (b) Compute the
tamaranim1 [39]

Answer:

Explanation:

Given data in question

mean stress  = 50 MPa

amplitude stress  = 225 MPa

to find out

maximum stress, stress ratio, magnitude of the stress range.

solution

we will find first  maximum stress  and minimum stress

and stress will be sum of (maximum +minimum stress) / 2

so for stress 50 MPa and 225 MPa

\sigma _{m} =  \sigma _{maximum} + \sigma _{minimum}  / 2

50 =  \sigma _{maximum} + \sigma _{minimum}  / 2    ...........1

and

225 =  \sigma _{maximum} + \sigma _{minimum}  / 2      ...........2

from eqution 1 and 2 we get maximum and minimum stress

\sigma _{maximum} = 275 MPa        ............3

and \sigma _{minimum} = -175 MPa     ............4

In 2nd part we stress ratio is will compute by ratio of equation 3 and 4

we get ratio =  \sigma _{minimum} / \sigma _{maximum}

ratio = -175 / 227

ratio = -0.64

now in 3rd part magnitude will calculate by subtracting maximum stress - minimum stress i.e.

magnitude = \sigma _{maximum} - \sigma _{minimum}  

magnitude = 275 - (-175) = 450 MPa

3 0
3 years ago
Two parallel surfaces move in opposite directions relative to each other at a velocity of 64 in/sec and are separated by a gap o
Illusion [34]

Answer:

\mu = 2.6906 × 10^{-3} lb-s/in²

Explanation:

given data

velocity V = 64 in/sec

separated by a gap x = 0.41 in

relative motion by shear stress \tau  = 0.42 lb/in²

solution

we know that shear stress is directly proportional to rate of change of velocity  as per newton's law of viscosity.

\tau = \mu \times \frac{du}{dy}      ....................1

so here \mu coefficient of dynamic viscosity and \frac{du}{dy} is velocity gradient

and

\tau = \mu \times \frac{v1 - v2 }{h2-h0}  

put here value and we get

0.42 =  \mu \times \frac{64}{0.41}

\mu = 2.6906 × 10^{-3} lb-s/in²

4 0
3 years ago
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