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3 years ago

How does an electroscope detect negative static electricity

1 answer:

5 0

<span> An electroscope that might have a static charge is tested on a metal surface. From there, the charges move to the metal and straight to the foil leaves. If they repel, or move away from each other, that means they have identical charges. This applies for both positive and negative static electricity.

work cited: School of champions, Google
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What is the force of a 13kg ball that has been dropped and has fallen for 1 second?

ankoles [38]

Answer:

127.4 newtons

Explanation:

Assuming g = 9.8:

F = ma = 13(9.8) = 127.4 N

6 0

3 years ago

A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart

Musya8 [376]

1) $0.61 m/s^2$

2) 13.9 s

Explanation:

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

$g=\frac{GM}{r^2}$ (1)

where

G is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

$r=4R$

where

$R=6.37\cdot 10^6 m$ is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

$g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2$

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

$g=0.61 m/s^2$ is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

$T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s$

4 0

3 years ago

I NEED HELP BADLY

Marrrta [24]

Answer:

a) Andrea's initial momentum, 200 kg m/s

b) Andrea's final momentum, 0

c) Impulse, = - 200 Ns

d) The force that the seat belt exerts on Andrea, - 400 N

Explanation:

Given data,

The initial velocity of the car is, u = 40 m/s

The mass of Andrea, m = 50 kg

The time period of deceleration, a = 0.5 s

The final velocity of the car, v = 0

a) Andrea's initial momentum,

p = mu

= 50 x 40

= 200 kg m/s

b) Andrea's final momentum

P = mv

= 50 x 0

= 0 kg m/s

c) Impulse

I = mv - mu

= 0 - 200

= - 200 Ns

The negative sign indicated that the momentum is decreased.

d) The force that the seat belt exerts on Andrea

F = (mv - mu)t

= (0 - 200) / 0.5

= - 400 Ns

Hence,the force that the seat belt exerts on Andrea is, - 400 N

7 0

3 years ago

I need help figuring out the science question!!

Aleonysh [2.5K]

Answer:

Explanation:

Speed is the distance covered over the time taken to do so.

s = d/t = 45 m / 3 s = 15 m/s

6 0

3 years ago

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.

grin007 [14]

<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium

RI = 1/0.6 = 5/3 or 1.66

3 0

3 years ago

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