The beam is refracted at 53.17-degree angle (asin 0.800414 = 53.17-degree). This problem can be solved by using the Snell's Law which described the refracted beam angle which traveled through a different media, in this case, through water and air. The formula of Snell's Law is stated as n1 sin θ1= n2 sin θ2. In this formula n1 is the refraction index of medium 1, θ1 is the normal light angle in the medium 1, n2 is the refraction index of medium 2, and θ2 is the normal light angle in the medium 2<span>. </span>
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Here's what I got to question A and B
a) Fs(max)=(0.560)(88.9N)=49.8N Fy=88.9N-49.8N=39.1N Fx=(39.1N)/(cos(40))=51.0N sqrt{39.1^2+51.0^2}=F
F=64.3N
b) 88.9N +49.8 N=138.7N=Fy Fx=(138.7N)/(cos(40))=181.06N sqrt{138.7^2+181.06^2}=F
F=228N
Is An object completely submerged in a fluid displaces its own volume of fluid ". This is: D