Answer:
2.78 m
Explanation:
At the peak, the velocity is 0.
Given:
a = -1.6 m/s²
v₀ = 2.98 m/s
v = 0 m/s
x₀ = 0 m
Find:
x
v² = v₀² + 2a(x - x₀)
(0 m/s)² = (2.98 m/s)² + 2(-1.6 m/s²) (x - 0 m)
x = 2.775 m
Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.
The statement about pointwise convergence follows because C is a complete metric space. If fn → f uniformly on S, then |fn(z) − fm(z)| ≤ |fn(z) − f(z)| + |f(z) − fm(z)|, hence {fn} is uniformly Cauchy. Conversely, if {fn} is uniformly Cauchy, it is pointwise Cauchy and therefore converges pointwise to a limit function f. If |fn(z)−fm(z)| ≤ ε for all n,m ≥ N and all z ∈ S, let m → ∞ to show that |fn(z)−f(z)|≤εforn≥N andallz∈S. Thusfn →f uniformlyonS.
2. This is immediate from (2.2.7).
3. We have f′(x) = (2/x3)e−1/x2 for x ̸= 0, and f′(0) = limh→0(1/h)e−1/h2 = 0. Since f(n)(x) is of the form pn(1/x)e−1/x2 for x ̸= 0, where pn is a polynomial, an induction argument shows that f(n)(0) = 0 for all n. If g is analytic on D(0,r) and g = f on (−r,r), then by (2.2.16), g(z) =
bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci
Answer:
Given:
Initial speed (u) = 10 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 3s
To Find:
Final speed (v) of the car
Explanation:
From equation of motion we have:
By substituting value of u, a & t in the equation we get:
Final speed (v) of the car = 16 m/s
