Answer:
455 Kcal
Explanation:
2Cl2(g) + 7O2(g) + 130kcal → 2Cl2O7(g)
Rearranging we get,
2Cl2(g) + 7O2(g) → 2Cl2O7(g) Δ H = 130 kcal . mol⁻¹
So for per mol reaction will be as above.
In case of 7 mols of product, we need 7/2 mole ratio x 130 = 455 Kcal
Answer is: pH of hydroxylamine solution is 9,23.
Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M =
0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.
c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).
0,0000000066 = x² / (0,05 mol/L - x).
solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
pH = 14 - 4,74 = 9,23.</span>
Answer:
A. Can A will make a louder and stronger fizz than can B.
Explanation:
The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.
The warmer can will be under greater pressure, so it will make a louder and stronger fizz.
From each drop-down menu, a solid has (a definite volume and a definite shape), a Liquid has (a definite volume) and gas has ( non of the above)
<h3>The features of different states of Matter:</h3>
Matter is defined as anything that has weight and occupies space.
There are three states of matter that is in existence which include:
- Solid: The particles of solid are closely packed together and vibrate around fixed axes. That is why they have a definite shape and volume.
- Liquid: The particles of liquid, though attracted to each other,move freely over each other. That is why they have definite volume but not a definite shape.
Therefore, a liquid occupies the shape of its container.
- Gas: The particles of gas contain scattered molecules that are dispersed across a given volume.
Therefore, a gas neither has a definite shape nor volume.
Learn more about matter here:
brainly.com/question/3998772
The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
= freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =
Now Depression in freezing point for sodium chloride is given by:
= Depression in freezing point
= freezing point constant
m= molality = 
Thus vant hoff factor for sodium chloride in X is 1.9
