Abdominal breathing is a condition in which only the inferior half of the lungs can be seen expanding and contracting with each
1 answer:
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Let's start by using the mirror equation:
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
from which we find q=13.6 cm.
The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.
Then we can also find the size of the image with respect to the original object. The magnification is given by
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
from which we find q=13.6 cm.
The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.
Then we can also find the size of the image with respect to the original object. The magnification is given by
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.
Answer:
Explanation:
From the question, acceleration from in 10 seconds.
Acceleration function can be written as:-
From the acceleration equation, we can obtain the velocity equation:
We calculate velocity after 10sec from the above v(t) as .
To obtain distance travelled after 10 seconds:-
Therefore 200m is for 10seconds, and next 200m at 30m/s
Total time=
Answer:
e. The amount of the charge decreases, because the capacitance decreases.
Explanation:
The capacitance of a parallel plate capacitor is given by the formula:
where is the permittivity of the medium between the plates, A the area of the plates and d the separation between them, so <em>if we increase the separation d the capacitance C will decrease</em>.
The relationship between the charge on the plate Q and the voltage applied V (the potential difference between the plates) is given by:
This means that if while <em>keeping the potential difference between the plates V constant the capacitance C decreases then the charge Q will decrease as well</em>.