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xxTIMURxx [149]
3 years ago
7

________ energy is the energy of the motion or vibration of molecules in a substance.

Physics
2 answers:
8_murik_8 [283]3 years ago
7 0
<span>Heat energy is the energy of the motion or vibration of molecules in a substance. The answer is letter A. A wrecking ball on its way down before it hits a building is an example of kinetic energy being converted into mechanical energy. The answer is letter D.</span>
tamaranim1 [39]3 years ago
4 0

The answer to the first question is A. Heat, because in order to heat up or catch fire, the molecules have to vibrate quickly.

This wrecking ball is an example of potential energy being converted into kinetic energy, so your answer is B. potential, kinetic.

Source: I have had to answer both questions before.

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A normal mode of a closed system is an oscillation of the system in which all parts oscillate at a single frequency. In general
valentina_108 [34]

Answer:

Explanation:

(A)

The string has set of normal modes and the string is oscillating in one of its modes.

The resonant frequencies of a physical object depend on its material, structure and boundary conditions.

The free motion described by the normal modes take place at the fixed frequencies and these frequencies is called resonant frequencies.

Given below are the incorrect options about the wave in the string.

• The wave is travelling in the +x direction

• The wave is travelling in the -x direction

• The wave will satisfy the given boundary conditions for any arbitrary wavelength \lambda_i

• The wave does not satisfy the boundary conditions y_i(0;t)=0&#10;

Here, the string of length L held fixed at both ends, located at x=0 and x=L

The key constraint with normal modes is that there are two spatial boundary conditions,y(0,1)=0&#10;

and y(L,t)=0

.The spring is fixed at its two ends.

The correct options about the wave in the string is

• The wavelength \lambda_i  can have only certain specific values if the boundary conditions are to be satisfied.

(B)

The key factors producing the normal mode is that there are two spatial boundary conditions, y_i(0;t)=0 and y_i(L;t)=0, that are satisfied only for particular value of \lambda_i  .

Given below are the incorrect options about the wave in the string.

•  A_i must be chosen so that the wave fits exactly o the string.

• Any one of  A_i or \lambda_i  or f_i  can be chosen to make the solution a normal mode.

Hence, the correct option is that the system can resonate at only certain resonance frequencies f_i and the wavelength \lambda_i  must be such that y_i(0;t) = y_i(L;t)=0&#10;

(C)

Expression for the wavelength of the various normal modes for a string is,

\lambda_n=\frac{2L}{n} (1)

When n=1 , this is the longest wavelength mode.

Substitute 1 for n in equation (1).

\lambda_n=\frac{2L}{1}\\\\2L

When n=2 , this is the second longest wavelength mode.

Substitute 2 for n in equation (1).

\lambda_n=\frac{2L}{2}\\\\L

When n=3, this is the third longest wavelength mode.

Substitute 3 for n in equation (1).

\lambda_n=\frac{2L}{3}

Therefore, the three longest wavelengths are 2L,L and \frac{2L}{3}.

(D)

Expression for the frequency of the various normal modes for a string is,

f_n=\frac{v}{\lambda_n}

For the case of frequency of the i^{th} normal mode the above equation becomes.

f_i=\frac{v}{\lambda_i}

Here, f_i is the frequency of the i^{th} normal mode, v is wave speed, and \lambda_i is the wavelength of i^{th} normal mode.

Therefore, the frequency of i^{th} normal mode is  f_i=\frac{v}{\lambda_i}

.

6 0
3 years ago
If the Earth got closer to the Sun, how would the gravity between the Sun and Earth change?
Neko [114]

Answer:

I think its 2. It would decrease

Explanation:

Hope this helps

4 0
3 years ago
Read 2 more answers
A car travels 240km in 4h what’s the cars velocity
Tresset [83]

The car's speed is 240km/4hr= 60km/hr.

There's not enough information given in the question to determine its velocity.

6 0
3 years ago
Read 2 more answers
Large amplitude of sound vibrations will produce.....
user100 [1]

Answer:

louder sound.

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound

8 0
4 years ago
Find the pressure exerted by a 3000 N crate that has an area of 2m squared
ipn [44]
Pressure = Force/ Area = 3000/2 = 1500 pascal.
8 0
3 years ago
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