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Valentin [98]
2 years ago
13

a cylinder is filled with 10. 0 L of gas and a piston is put into it. The initial preasure of the gas is measured to be 138 kPa.

The piston is now pushed down compressing the gas until the gas has a final volume of 8.30 L calculate the final pressure of the gas be sure your answer has the correct number of significant digits.​
Chemistry
1 answer:
Scrat [10]2 years ago
8 0

Answer:

First you need to convert the cylinder to a boot, then you can successfully compress the water into the tip of the boot, preventing it from busting.

Explanation:

To convert a cylinder to a boot, simply multiply the circumference of the cylinder by 1.3125768927, or 1.31. The .31 is the extra space taken in by the tip of the boot.

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What type of bond holds the complementary bases together?.
olga55 [171]

Answer:

hydrogen bonding

Explanation:

The two strands of DNA are held together by hydrogen bonds between complimentary nucleotides.

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2 years ago
A reading shows a pressure measurement of 43 in. Hg. What is the equivalent pressure in psi? A. 5.73 psi B. 2223.13 psi C. 26.32
oksian1 [2.3K]
43 inHg = 43 inHg*2.54cm/in = 109.22cmHg * 10 mm/cm = 1092.2 mmHg


14.7 psi = 760 mmHg

1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi

Answer: option D. 21.13 psi
7 0
3 years ago
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3. A student measured 15.0 grams of ice in a beaker. The beaker was then
gregori [183]

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

3 0
3 years ago
How many molecules of O2 are required to react with 3.00 moles P4?<br> P4+5O2⟶2P2O5
likoan [24]

Answer:

1400

Explanation:

8 0
3 years ago
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If 45 mL of water are added to 250 mL of a 0.75 M K2SO4 solution, what will the molarity of the diluted solution be?
krok68 [10]

Answer:

\large\boxed{\large\boxed{0.64M}}

Explanation:

When you form a <em>diluted solution</em> from a mother (concentrated) solution, the moles of solute are determined by the mother solution.

The main equation is:

Molarity=\dfrac{\text{moles of solute}}{\text{volume of the solution in liters}}

Then, since the moles of solute is the same for both the mother solution and the diluted solution:

          \text{Molarity mother solution }\times\text{ volume mother solution}=\\\\=\text{Molarity diluted solution }\times\text{ volume diluted solution}

Substitute and solve for the molarity of the diluted solution:

           250mL\times 0.75M=(45mL+250mL)\times M\\\\\\M=\dfrac{250mL\times 0.75M}{295mL}=0.64M

8 0
3 years ago
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