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Valentin [98]
2 years ago
13

a cylinder is filled with 10. 0 L of gas and a piston is put into it. The initial preasure of the gas is measured to be 138 kPa.

The piston is now pushed down compressing the gas until the gas has a final volume of 8.30 L calculate the final pressure of the gas be sure your answer has the correct number of significant digits.​
Chemistry
1 answer:
Scrat [10]2 years ago
8 0

Answer:

First you need to convert the cylinder to a boot, then you can successfully compress the water into the tip of the boot, preventing it from busting.

Explanation:

To convert a cylinder to a boot, simply multiply the circumference of the cylinder by 1.3125768927, or 1.31. The .31 is the extra space taken in by the tip of the boot.

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A 151.5-g sample of a metal at 75.0°C is added to 151.5 g at 15.1°C. The temperature of the water rises to 18.7°C. Calculate the
Kryger [21]

Answer:

The specific heat capacity of the metal is 0.268 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 151.5 grams

The temperature of the metal = 75.0 °C

Temperature of water = 15.1 °C

The temperature of the water rises to 18.7°C.

The specific heat capacity of water is 4.18 J/°C*g

Step 2: Calculate the specific heat capacity of the metal

heat lost = heat gained

Q = m*c*ΔT

Qmetal = - Qwater

m(metal) * c(metal) * ΔT(metal) = m(water) * c(water) * ΔT(water)

⇒ mass of the metal = 151.5 grams

⇒ c(metal) = TO BE DETERMINED

⇒ΔT( metal) = T2 - T1 = 18.7 °C - 75.0 °C = -56.3 °C

⇒ mass of the water = 151.5 grams

⇒ c(water) = 4.184 J/g°C

⇒ ΔT(water) = 18.7° - 15.1 = 3.6 °C

151.5g * c(metal) * -56.3°C = 151.5g * 4.184 J/g°C * 3.6 °C

c(metal) = 0.268 J/g°C

The specific heat capacity of the metal is 0.268 J/g°C

5 0
3 years ago
I need help solving this for chemistry. Don’t know where to start:/
Juli2301 [7.4K]
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1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

One ion Co²⁺   takes 2e⁻ to become Co⁰.
1 mol of Co²⁺  ions take 2 mole of e⁻ to become Co⁰, so
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9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
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