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lozanna [386]
3 years ago
10

How much positive charge is in 0.9 kg of carbon? The atomic weight (12.0107 g) of carbon contains Avogadro’s number of atoms, wi

th each atom having 6 protons and 6 electrons. The elemental charge is 1.602 × 10−19 C and Avogadro’s number is 6.023 × 1023 . Answer in units of C.
Chemistry
1 answer:
hram777 [196]3 years ago
5 0

Answer:

The positive charge in carbon is =4338.11 \times 10^{4} C

Explanation:

Atomic weight: An atom consists of protons, neutrons and electrons. Atomic mass is the sum of the number of protons and neutrons. The average weight of mass is called atomic mass of that atom.

The positive charge of an atom is proton.

The atomic weight of carbon = 12.0107 g/mol

Avogadro's number = 6.023×10⁻²³ atom/ mol

Charge = 1.602×10⁻¹⁹ C

The weight of carbon = 0.9 kg = 900 gram

Number of protons in carbon = 6

The positive charge in carbon is

=No. mole× Avogadro's Number× No. proton × charge per proton

=\frac {900g}{12.0107g/mol}\times( 6.023 \times10^{23} atom/mol) \times6 \times (1.602\times10^{-19}C)

=4338.11 \times 10^{4} C

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4.50 g of NaCl reacts with 10.00 g of AgNO3 to produce 7.93 g of AgCl. If the theoretical amount of AgCl that can be formed is 8
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Answer: 94.07%

Explanation:

Percentage yield can be calculated by the formula

%yield = Experimental yield/Theoretical yield x100

Experimental yield = 7.93g

Theoretical yield = 8.43

%yield = Experimental yield/Theoretical yield x100

%yield = 7.93/8.43 x 100 = 94.07%

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3 years ago
15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams
sveticcg [70]

Answer:

\boxed {\tt A. \ d=0.85 \ g/mL}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

m= 12.7 \ g\\v= 15 \ mL

Substitute the values into the formula.

d=\frac{12.7 \ g}{ 15 mL}

Divide.

d=0.846666667 \ g/mL

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

d \approx 0.85 \ g/mL

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
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<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

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Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
3 years ago
How many moles are there in 5.699 liters of neon gas at STP? Express your answer with the appropriate significant figures and un
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Answer:

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Explanation:

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5.699L consists of \frac{5.699}{22.4} = 0.25442 moles.

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