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Rzqust [24]
3 years ago
6

How do you answer this question 3/4b +10=20

Mathematics
2 answers:
noname [10]3 years ago
7 0
1) move the 10 over
So it becomes
3/4b = 10
2) multiply everything by 4 to get rid of the denominator
2b = 40
3) divide both sides by 2
b = 20
Volgvan3 years ago
4 0

\frac{3}{4}b+10=20 \ \ \ \ | - 10\\\\ \frac{3}{4}b=10 \ \ \ \ | \cdot4\\\\3b=40 \ \ \ \ | : 3\\\\b=\frac{40}{3}\\\\ b=13\frac{1}{3}

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2 years ago
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What is the x value such that y =15 - 3x and y = 0? Please explain how you got this answer.
ICE Princess25 [194]

Answer:

x=5

Step-by-step explanation:

So how i came about to get this answer, was

y=15-3x

y=15-3(5)

y=15-15

y=0

I found five by testing out different numbers for x such as 1 2 3 4, but when i got to five, that was where i got the answer, as shown above.

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3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! <br><br> What is (f/g)(x) ?
Rudiy27

Answer:   \bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x


\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}

Restriction on x: the denominator cannot be equal to zero. So,

    x(3x - 2) ≠ 0  

→  x ≠ 0     and     3x - 2 ≠ 0

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8 0
3 years ago
Angle 1 and Angle 2 are supplementary. Angle 1 is 20 degree less than nine times the size of angle 2.
nadya68 [22]

Answer:

∠1=160° and ∠2=20°

Step-by-step explanation:

Let ∠1 = x

∠2 = y

as these two angles are supplementary their sum is 180

that x+y=180   ----(A)

Also given that ∠1 is 20 degree less than nine times the size of ∠2.

Hence

x=9y-20

putting value of x in A and solving for y

9y-20+y=180

10y=180+20

10y=200

y=10

Putting this y in A

x+10=180

x=160

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3 years ago
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Answer:

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