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wolverine [178]
3 years ago
7

Physical quantity are measurable quantities

Physics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

yeah physical quantities are the quantities which can be meaured

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The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to Earth's Moon. Their orbital radii
tankabanditka [31]

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0.2528

Explanation:

To calculate the period we need the formula:

T=\frac{2\pi r^{3/2}}{\sqrt{GM}}

Where r is the radius of the moon, G is the universal constant of gravitation and M is the mass of mars.

The period of Phobos:

T_{p}=\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}

The period of Deimos:

T_{D}=\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}

The ratio of the period of Phobos and Deimos:

\frac{T_{p}}{T_{D}}=\frac{\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}}{\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}}

\frac{T_{p}}{T_{D}}=\frac{\sqrt{GM}2\pi r_{p}^{3/2}}{\sqrt{GM}2\pi r_{D}^{3/2}}

Most terms get canceled and we have:

\frac{T_{p}}{T_{D}}=\frac{r_{p}^{3/2}}{r_{D}^{3/2}}

According to the problem

r_{p}=9,378km\\r_{D}=23,459km

so the ratio will be:

\frac{T_{p}}{T_{D}}=\frac{(9,378)^{3/2}}{(23,459)^{3/2}}=\frac{908166.22}{3593058.125}=0.25275 ≈ 0.2528

the ratio of the period of revolution of Phobos to that of Deimos is 0.2528

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3 years ago
How much heat does 56 L of water need to absorb to raise its temperature from 350C to 740C?​
LekaFEV [45]

Answer:

300 L of water

Explanation:

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