Answer: IBr has the smallest percentage ionic character amongst the given compounds.
Explanation: Percentage ionic character is calculated by using the formula:
....(1)
where, = difference in the electronegativies of the element forming a compound.
Electronegativity of H = 2.1
Electronegativity of F = 3.98
Electronegativity of Li = 0.98
Electronegativity of I = 2.66
Electronegativity of Br = 2.96
Electronegativity of Cl = 3.16
Putting this in equation 1, we get:
Putting this in equation 1, we get:
Putting this in equation 1, we get:
Putting this in equation 1, we get:
From the above calculations, we see that IBr has the smallest percent ionic character.