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3 years ago

What else is produced during the combustion of butane, C4H10? 2C4H10 + 13O2 → + 10H2O

Chemistry

2 answers:

Neko [114]3 years ago

8 0

<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

Butane, C₄H₁₀

Butane is a hydrocarbon in the homologous series known as alkane.

We are required to determine the other product produced in the combustion of butane apart from water.

We know that the complete combustion of alkane yields carbon dioxide and water.
Therefore, combustion of butane will yield carbon dioxide and water.

The balanced equation for the complete combustion of butane will be;

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

AveGali [126]3 years ago

7 0

Answer:

8CO2

Explanation:

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there are 2970000cm in 29.7km

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3 years ago

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SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$ .....(1)

Molarity of $HCl$ solution = 0.75 M

Volume of $HCl$ solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

$\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles$

$CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)$

According to stoichiometry :

2 moles of $HCl$ require = 1 mole of $CaCO_3$

Thus 0.01875 moles of $HCl$ will require= $\frac{1}{2}\times 0.01875=0.009375moles$ of $CaCO_3$

Mass of $CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g$

Thus 0.9375 g of $CaCO_3$ is required to react with 25.0 ml of 0.75 M HCl

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3 years ago

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Paul [167]

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3 years ago

How many moles are in a 275g sample of K2CrO3

Marrrta [24]

Answer:

There are approximately 1.54 moles in a 275 g sample of $K_2CrO_3$ .

Explanation:

To find out number of moles, fistly we have to calculate molecular mass of $K_2CrO_3$ .

There are 2 atoms of Potassium 1 atom of Chromium and 3 atoms of oxygen in the given compound.

For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.

Atomic mass of Potassium = 39

Atomic mass of Chromium = 52

Atomic mass of Oxygen = 16

Now,

Molecular mass of $K_2CrO_3$ = $2\times 39+52+3\times 16=78+52+48=178\ gm$

The molecular mass of a compound is the mass of compound in one mole.

To find out the number of moles, we have to divide given mass of compound by its molecular mass.

$Number\ of\ moles=\frac{given\ mass}{molecular\ mass}$

$Number\ of\ moles=\frac{275}{178}= 1.54$

Hence the number of moles in 275 gm of $K_2CrO_3$ is 1.54.

8 0

3 years ago

Wewaii [24]

Answer: 0.0450 moles of $CaCl_2$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of} CaCl_2=\frac{5.00g}{110.98g/mol}=0.0450moles$

Thus there are 0.0450 moles of $CaCl_2$

6 0

3 years ago