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3 years ago

What else is produced during the combustion of butane, C4H10? 2C4H10 + 13O2 → + 10H2O

Chemistry

2 answers:

Neko [114]3 years ago

8 0

<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

Butane, C₄H₁₀

Butane is a hydrocarbon in the homologous series known as alkane.

We are required to determine the other product produced in the combustion of butane apart from water.

We know that the complete combustion of alkane yields carbon dioxide and water.
Therefore, combustion of butane will yield carbon dioxide and water.

The balanced equation for the complete combustion of butane will be;

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

AveGali [126]3 years ago

7 0

Answer:

8CO2

Explanation:

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Which type of chemical model shows the bond angle and bond length between atoms and compounds?

ELEN [110]

A molecular structure also shows the bond angle and the Bond length between different atoms in a compound.

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3 years ago

The ph of a solution containing 0.818 M acetic acid (ka1.76*10-5) ans 0.172 M sodium acetate is?

kvasek [131]

Explanation:

It is known that the relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log \frac{[salt]}{[acid]}$

and, $pK_{a} = -log K_{a}$

Hence, first we will calculate the value of $pK_{a}$ as follows.

$pK_{a} = -log K_{a}$

= $-log (1.76 \times 10^{-5}$

= 4.75

Now, we will calculate the value of pH as follows.

pH = $pK_{a} + log \frac{[\text{sodium acetate}]}{\text{acetic acid}}$

= $4.75 + log \frac{0.172}{0.818}$

= 4.75 + (-0.677)

= 4.07

Therefore, we can conclude that the pH of given solution is 4.07.

5 0

3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

Answer: The mass of lead iodide produced is 9.22 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

6 0

3 years ago

A chemical indicator that changes colors depending on the concentration of h+ in the solution is called a

DanielleElmas [232]

Answer is: acid-base indicator or pH indicators.

Acid-base indicators are usually weak acids or bases and they are chemical detectors for hydrogen or hydronium cations.
Example for acid-base indicator is phenolphthalein (molecular formula C₂₀H₁₄O₄). Phenolphthalein is colorless in acidic solutions and pink in basic solutions.
Another example is methyl orange. It is red colour in acidic solutions and yellow colour in basic solutions.

3 0

3 years ago

When you have finished adding the necessary amount of NaOH to your beaker, what color will the litmus paper turn?

Svetllana [295]

Answer: The red litmus paper turns blue on dipping in NaOH solution.

Explanation:

Litmus paper is the indicator that detects the nature of the solution, whether it is acidic or basic.

There are 2 types of litmus paper:

Red litmus paper: This paper will turn blue if it is dipped in basic solution and will remain as such if it is dipped in acidic solution.
Blue litmus paper: This paper will turn red if it is dipped in acidic solution and will remain as such if it is dipped in basic solution.

NaOH is a strong base, so when a red litmus paper is dipped in the beaker having necessary amount of NaOH, the red litmus paper turns into blue.

7 0

3 years ago