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Ber [7]
3 years ago
13

What else is produced during the combustion of butane, C4H10? 2C4H10 + 13O2 → + 10H2O

Chemistry
2 answers:
Neko [114]3 years ago
8 0
<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

  • Butane, C₄H₁₀
  • Butane is a hydrocarbon in the homologous series known as alkane.

We are required to determine the other product produced in the combustion of butane apart from water.

  • We know that the complete combustion of alkane yields carbon dioxide and water.
  • Therefore, combustion of butane will yield carbon dioxide and water.
  • The balanced equation for the complete combustion of butane will be;

       2C₄H₁₀ + 13O₂ →  8CO₂ + 10H₂O

AveGali [126]3 years ago
7 0

Answer:

8CO2

Explanation:

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likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

Therefore,

1.3075 gross = 1.3075 gross × 12 dozen / 1 gross

1.3075 gross = 15.69 dozen

Thus, 5 g of penny is equivalent to 15.69 dozen

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Help needed Assignment is due Justify that H2SO4 is Arrhenius acid and KOH is Arrhenius base.
irakobra [83]

Answer:

<u><em>Arrhenius Acid:</em></u>

According to Arrhenius concept, Acids are proton donors.

Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.

See the following reaction =>

<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>

<u><em>Arrhenius Base:</em></u>

An Arrhenius base is a a proton acceptor.

KOH accepts the proton to to made to KOH₂ and a proton acceptor.

See the following reaction =>

<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>

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Answer:

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