Answer:
3.86×10⁶ Newton/coulombs
Explaination:
Applying,
E = F/q....................... Equation 1
Where E = Electric Field, F = Force, q = charge.
From the question,
Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs
Substitute these values into equation 1
E = 5.4×10⁻¹/ -1.4×10⁻⁷
E = -3.86×10⁶ Newtons/coulombs
Hence the magnitude of the electric field created by the
negative test charge is 3.86×10⁶ Newton/coulombs
Answer:
The radius of a chamber is 2.36 meters.
Explanation:
Given that,
The outer wall moves at a speed of 2.72 m/s.
Mass of the person, m = 75.1 kg
The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

r is the radius of a chamber


r = 2.36 meters
So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.
Answer:
<h3>The answer is 2.0 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 100 g
volume = 50 mL
We have

We have the final answer as
<h3>2.0 g/mL</h3>
Hope this helps you