Bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Answer:
Mole percent of
in solution is 1.71%
Explanation:
Number of moles of a compound is the ratio of mass to molar mass of the compound.
Molar mass of
= 110.98 g/mol
Molar mass of
= 18.02 g/mol
Density is the ratio of mass to volume
So, mass of 60.0 mL of water = 
Hence, 6.50 g of
=
of
= 0.0586 moles of 
60.8 g of
=
of
= 3.37 moles of 
So, mole percent of
in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% =
% = 1.71%
Answer:
32.4 L
Explanation:
Note 1:
The Standard Temperature and Pressure (STP) is defined by IUPAC as air at 0 gradius Celcius and 1 bar.
Note 2:
The Ideal Gas Law is used for solving this problem.
......
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!