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3 years ago

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Engineering

1 answer:

hoa [83]3 years ago

3 0

Answer:

Engineering is the use of scientific principles to design an build machines, structure, an other item including bridges, tunnels, road etc

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A 50 Ibm block is moving at 4 ft/s. Find Its total kinetic energy? Also find Its kinetic energy per unit mass is

Kamila [148]

Answer:

Total kinetic energy= 400 puondal foot

Kinetic energy per unit mass= 8 (poundaul foot/lb)

Explanation:

To determine the total kinetic energy of the block we use the equation:

Kinetic energy = (1/2) × m × (v^{2}) = (1/2) × (50lb) × (4 foot/s)^{2}) =

= 400 poundal foot

To establish the kinetic energy per unit of mass we must simply divide the value of the total kinetic energy obtained previously by the mass of the block obtaining:

Kinetic energy per unit mass= (400 poundal foot) / (50lb) =

= 8 (poundaul foot/lb)

3 0

3 years ago

State two reasons why industrial files must be always be used fitted upon the individual

NikAS [45]

Explanation:

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4 0

3 years ago

In a tensile test on a steel specimen, true strain = 0.12 at a stress of 250 MPa. When true stress = 350 MPa, true strain = 0.26

scZoUnD [109]

Answer:

The strength coefficient is $625$ and the strain-hardening exponent is $0.435$

Explanation:

Given the true strain is 0.12 at 250 MPa stress.

Also, at 350 MPa the strain is 0.26.

We need to find $(K)$ and the $(n)$ .

$\sigma =K\epsilon^n$

We will plug the values in the formula.

$250=K\times (0.12)^n\\350=K\times (0.26)^n$

We will solve these equation.

$K=\frac{250}{(0.12)^n}$ plug this value in $350=K\times (0.26)^n$

$350=\frac{250}{(0.12)^n}\times (0.26)^n\\ \\\frac{350}{250}=\frac{(0.26)^n}{(0.12)^n}\\ \\1.4=(2.17)^n$

Taking a natural log both sides we get.

$ln(1.4)=ln(2.17)^n\\ln(1.4)=n\times ln(2.17)\\n=\frac{ln(1.4)}{ln(2.17)}\\ n=0.435$

Now, we will find value of $K$

$K=\frac{250}{(0.12)^n}$

$K=\frac{250}{(0.12)^{0.435}}\\ \\K=\frac{250}{0.40}\\\\K=625$

So, the strength coefficient is $625$ and the strain-hardening exponent is $0.435$ .

5 0

3 years ago

Consider a turbojet powered airplane flying at a standard altitude of 30,000ft at a velocity of 500 mph. The turbojet engine its

grandymaker [24]

Answer:

T = 20.42 N

Explanation:

given data

standard altitude = 30,000 ft

velocity Ca = 500 mph = 0.4 m/s

inlet areas Aa = 7 ft² = 0.65 m²

exit areas Aj = 4.5 ft² = 0.42 m²

velocity at exit Cj = 1600 ft/s = 487.68 m/s

pressure exit $\rho$ j = 640 lb/ft² = 0.3 bar

solution

we get here thrust of the turbojet that is express as

thrust of the turbojet T = Mg × Cj - Ma × Ca + ( $\rho$ j Aj - $\rho$ a Ag ) .............1

here Ma = Mg

Ma = $\rho$ a × Ca Aa = 0.042 kg/s

put value in equation 1 we get

T = 0.042 × (487.68 -0.14) + ( 0.3 × - 0.3 × 0.65 )

T = 20.42 N

5 0

3 years ago

The function below takes a single parameter, a list of numbers called number_list. Complete the function to return a string of t

makkiz [27]

Answer:

The solution code is written in Python:

def convertCSV(number_list):
str_list = []
for num in number_list:
str_list.append(str(num))
return ",".join(str_list)
result = convertCSV([22,33,44])
print(result)

Explanation:

Firstly, create a function "convertCSV" with one parameter "number_list". (Line 1)

Next, create an empty list and assign it to a new variable str_list. (Line 2)

Use for-loop to iterate through all the number in the number_list.(Line 4). Within the loop, each number is converted to a string using the Python built-in function str() and then use the list append method to add the string version of the number to str_list.

Use Python string join() method to join all the elements in the str_list as a single string. The "," is used as a separator between the elements (Line 7) . At the end return the string as an output.

We can test the function by calling the function and passing [22,33,34] as an argument and we shall see "22,33,44" is printed as an output. (Line 9 - 10)

6 0

3 years ago