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leonid [27]
3 years ago
7

Which are the most common producers in aquatic ecosystems?

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

b -algae

Explanation:

The most common producers in aquatic ecosystems are the algae. They are called phytoplanktons.

  • In the food web and food chain of aquatic ecosystems, they usually set out with the algae.
  • These algae are called phytoplanktons.
  • They are the producers in all aquatic ecosystem.
  • Phytoplanktons consists of algae and cyanobacteria.
  • Just like plants on land, phytoplanktons manufacture food in an aquatic ecosystem.
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I have this sheet and I don’t understand any of it at all
katen-ka-za [31]

I know this probably is not what you are looking for, but this is what I would suggest.

Write down on the side what values they are giving you and the corresponding variable used for that value.

Like for the first question, they give you mass is 3000kg.

On the side write

m = 3000kg

m is the variable used for mass

Then list any other variables they give you in the question and then what you are trying to look for.

a = 2m/s^2

F = ?

a is the variable for acceleration and F is the variable for force.

So now you have:

m = 3000kg

a = 2m/s^2

F = ?

You have a and m, and you are looking for F (force), you know that because it asks "with what force".

Also note, that you have to know what the variable is based on the units and you likely have some type of formula sheet with all of them listed.

You can use the variables and what is unknown to match it to a formula that will solve for the unknown variables. Also note, that it might not always be simply a=b+c, you may know what "a" and "b" are, but they may ask for c so you will have to rearrange the formula with some simple algebra.

This question however is simple. You can see you are going to use the formula

F=ma.

So now just substitute in your variables to solve for F.

(3000kg)(2m/s^2) = 6000N

<u>Make sure to write the units</u> which are probably on your formula sheet as well. Force is measured in Newtons, so you use the unit N.

Also note, if they gave you mass in grams (another unit), you cannot use that in the formula (your formula sheet would tell you the unit it must be in), so you would have to convert it to kg.

Hope this helps as a starting point. I don't intend to do your homework for you, but explain a process you can use to help you do it on your own.

3 0
3 years ago
What is the voltage across an 8.00 nm–thick membrane if the electric field strength across it is 5.50 MV/m?
polet [3.4K]

Answer:

0.044 V

Explanation:

E = Electric field = 5.5\times 10^6\ V/m

d = Thickness of membrane = 8 nm

When the electric field strength is multiplied by the membrane thickness we get the voltage

Voltage across a gap is given by

V=Ed\\\Rightarrow V=5.5\times 10^6\times 8\times 10^{-9}\\\Rightarrow V=0.044\ V

The voltage across the membrane is 0.044 V

4 0
3 years ago
Is diet Pepsi heterogeneous or is it homogeneous
Lana71 [14]
Heterogeneous because it has less amount of sugar than the regular Pepsi has
6 0
3 years ago
Read 2 more answers
If the charge remains the same but the radius of the sphere is doubled, the electric flux coming out of it will be
il63 [147K]

Answer:

Explanation:

We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .

∫ E ds = q / ε

Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so

∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .

This also represents total flux coming out of the charge q on all sides .

This is equal to q / ε where ε is a constant called permittivity  which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .

If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .

It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors

1 ) charge q and

2 ) the permittivity of medium  ε  around .

4 0
3 years ago
Scientists can use spectral analysis of stars to determine which of the following?
RoseWind [281]
I do believe all of these but core elements can be determined by spectroscopy which includes the use of electromagnetic radiation. Both the surface and core temperature can be measured using light. Surface elements can be found because the absorption lines of different elements in the spectra of the star, but I haven't heard anything about using spectral analysis for core elements.
4 0
3 years ago
Read 2 more answers
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