The working equation for this problem is written below:
x = v₀t + 0.5at², where x is the distance traveled, v₀ is the initial velocity, a is the acceleration and t is the time
Let's apply the concept of calculus. The maximum speed is equated to the derivative of x with respect to t.
dx/dt = 8 ft/s = v₀ + at
Since the it starts from rest, v₀ = 0
8 = at
t = 8/a
The net acceleration is 0.7 - 0.35 = 0.35 ft/s². Thus,
t = 8/0.35 = 22.86 seconds
Answer:
Explanation:
Given:
- angle of launch of projectile from horizontal,
- range of projectile,
<u>We have formula for the range of projectile:</u>
putting the respective values
is the velocity with which Tom should jump to land on the other roof.
Answer:
Explanation:
Check attachment for solution
light waves do not require a medium so A would be your answer good luck :)
Answer:
0.444atm
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (
P2 = final pressure (
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to this question,
P1 = 101.3 kPa = 101.3 × 0.00987 = 0.999atm
P2 = ?
V1 = 80L
V2 = 160L (double of V1)
T1 = 34°C = 34 + 273 = 307K
T2 = 0°C = 0 + 273 = 273K
Using P1V1/T1 = P2V2/T2
0.999 × 80/307 = P2 × 160/273
79.92/307 = 160P2/273
Cross multiply
307 × 160P2 = 79.92 × 273
49120P2 = 21818.16
P2 = 21818.16 ÷ 49120
P2 = 0.444
P2 = 0.444atm