Answer:
0.05 V/m
Explanation:
V = Potential difference that is possible for the dolphin to detect = 0.5 mV
d = Distance between electrodes = 1 cm
Electric field strength is given by



The corresponding electric field strength is 0.05 V/m
Answer:
0.05
Explanation:
Given a variable C which is the product of two variables A, B:

Then the absolute error on C is given by:
where
are the uncertanties on the measure of A, B and C, respectively.
In this problem, the horizontal component of the velocity
is given by

Therefore, the uncertainty on vx is given by:
(1)
where we have:


, so

The uncertainty on
is given by:

where:

and

So

Also,

So, combininb everything into (1), we find:

Answer:
F = 195 N
Explanation:
F = GMm/d²
F = 6.67e-11(5.97e24)(24) / (7.00e6)²
F = 195 N
The theory of blackbody radiation is shown by the equation. E= h×f
Where E = energy of the photon, f is the frequency of photon and h is equal to 6.63 ×10⁻³⁴ J.s in the plank constant. Light exists in form of a bundle of energy which is called photon and its energy is determined by frequency.
Therefore, any emission or absorption of light must involve discrete changes in energy of the system. Light is composed of discrete chunks that must be absorbed as a unit.
The product of (wavelength) x (frequency) is always the same number ... the wave's speed.
So if the wavelength is somehow reduced to 1/4 its original length, the <em>frequency is immediately multiplied by 4</em> . That's the only way their product can remain the same.