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mamaluj [8]
2 years ago
6

Name two types of Transformers.

Engineering
1 answer:
ipn [44]2 years ago
8 0
Bumblebee and Starscream
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Consider a cubic workpiece of rigid perfect plastic material with side length lo. The cube is deformed plastically to the shape
Taya2010 [7]

Answer:  ε₁+ε₂+ε₃ = 0

Explanation: Considering the initial and final volume to be constant which gives rise to the relation:-

                         l₀l₀l₀=l₁l₂l₃

                        \frac{lo*lo*lo}{l1*l2*l3}=1.0

                      taking natural log on both sides

                              ln(\frac{(lo*lo*lo)}{l1*l2*l3})=ln(1)

Considering the logarithmic Laws of division and multiplication :

                                ln(AB) = ln(A)+ln(B)

                                ln(A/B) = ln(A)-ln(B)

                           ln(\frac{(l1)}{lo})*ln(\frac{(l2)}{lo})*ln(\frac{(l3)}{lo}) = 0

Use the image attached to see the definition of true strain defined as

                         ln(l1/1o)= ε₁

which then proves that ε₁+ε₂+ε₃ = 0

8 0
3 years ago
What are the top 4 solar inventions, how they are used, and how they are better than the original way of powering them
OlgaM077 [116]
Yes I will answer soon
7 0
3 years ago
Voltage signals are generated on the output of a piezoelectric pressure transducer that is equipped with an amplifier.
Tema [17]

Answer: True

Explanation: Piezoelectric pressure transducers are equipments that helps to generate voltage through the mechanical actions such as applied pressure. Piezoelectric transducer is made up of quartz crystals which are made of silicone and oxygen formed in a crystalline structure.

Piezoelectric transducer can also be described as a Piezoelectric sensor as it helps to detect electric voltage generated through applied pressure.

8 0
3 years ago
What is a robot’s work envelope?
Dmitry_Shevchenko [17]

Answer:

B

Explanation:

A robot's work envelope is its range of movement. It is the shape created when a manipulator reaches forward, backward, up and down. These distances are determined by the length of a robot's arm and the design of its axes. ... A robot can only perform within the confines of this work envelope.

3 0
2 years ago
The numbers should be added to the merged array in an alternating pattern: first from list 1, then from list 2, then list 1 agai
Vinvika [58]

Answer:

According to the complete question, the code below gives the solution to the problem in Java with appropriate comments

Explanation:

import java.util.Scanner;

import java.lang.Math;

class Main {

  public static void main(String[] args) {

      int length = 0;

      boolean lengthCheck = true;

      Scanner scan = new Scanner(System.in);

      while (lengthCheck == true)

      {

          System.out.println("Enter an array length (must be 10 or greater):");

          length = scan.nextInt();

          if (length >= 10)

          {

              lengthCheck = false;

          }

      }

      int[] firstArray = new int[length];

      int[] secondArray = new int[length];

      System.out.print("\nFirst Array: ");

      for (int i = 0; i < length; i++)

      {

          firstArray[i] = (int) (Math.random() * 100) + 1;

          System.out.print(firstArray[i] + " ");

      }

      System.out.print("\n\nSecond Array: ");

      for (int i = 0; i < length; i++)

      {

          secondArray[i] = (int) (Math.random() * 100) + 1;

          System.out.print(secondArray[i] + " ");

      }

      System.out.println("\n");

     

     

/*

* A boolean array of length 100 to track list of number we have already added to merge list

*/

      boolean[] isAdded = new boolean[100];

      int[] merge = new int[(firstArray.length + secondArray.length)];

     

      int j=0;

      for (int i = 0; i < length; i++)

      {

          if(!isAdded[firstArray[i] - 1]) {

              merge[j] = firstArray[i];

              j++;

              isAdded[firstArray[i] - 1] = true;

          }

         

          if(!isAdded[secondArray[i] - 1]) {

              merge[j] = secondArray[i];

              j++;

              isAdded[secondArray[i] - 1] = true;

          }

         

      }

     

      System.out.print("Merged Array: ");

     

      for (int i = 0; i < 2*length && merge[i] != 0; i++)

      {

          System.out.print(merge[i] + " ");

      }

      System.out.println("\n");

     

  }

}

4 0
3 years ago
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