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2 years ago

Give two examples of elevation.

Chemistry

1 answer:

jasenka [17]2 years ago

5 0

Answer:

An example of elevation is a plane flying at 36,000 feet above the ground. An example of elevation is a pope being raised to the position of saint. An example of elevation is a ballet dancer leaping three feet in the air. ... At 8,850 m (29,028 ft), the summit of Mount Everest is the highest elevation on Earth.

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E. What is one way that your body knows if it is upside-down or not?

Firlakuza [10]

Answer:

You get some type of pressure that you start to feel in your muscles and joints from gravity and movement. How do they say it? Something called "seat-of-the-pants" (something like that). You get some type of pressure, and your body senses it, and it knows when you are upside-down or not, because if you're not, then you won't get any pressure in your muscle.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

6 0

3 years ago

For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o_{(Cu^{2+}/Cu)}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)$

$E^o_{(Cu^{2+}/Cu)}=0.34V$

Hence, the value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

8 0

3 years ago

__C2H4+__O2-->__CO2+__H2O

mihalych1998 [28]

Answer:

Here is your answer mate :D

3 0

2 years ago

What is the pH of a solution which is 0.600 M in dimethylamine ((CH3)2NH) and 0.400 M in dimethylamine hydrochloride ((CH3)2NH2C

Viefleur [7K]

Answer:

pH = 11.05

Explanation:

It is possible to answer this question using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A] / [HA⁺]

Where A in this case is weak base (dimethylamine) and conjugate acid (HA⁺) is dimethylamine hydrochloride.

As Ka= Kw / Kb = 1x10⁻¹⁴ / 7.4x10⁻⁴ = 1.35x10⁻¹¹ And pKa is -log Ka = 10.87 pH of the solution is:

pH = 10.87 + log₁₀ [0.600] / [0.400]

pH = 11.05

I hope it helps!

3 0

3 years ago

In water, hydrogen bonds are best described as _____.

Elina [12.6K]

Answer: Option D) covalent bonds between water molecules

In water, hydrogen bonds are best described as covalent bonds between water molecules

Explanation:

The hydrogen bonds between water molecules are covalent bonds because they are formed when oxygen attract the lone electron in hydrogen, thus resulting in the formation of a partially negative charge on the oxygen atom and a partially positive charge on two hydrogen atoms

Thus, the sharing of electrons between oxygen and hydrogen atoms is responsible for the covalent bonds between water molecules

7 0

2 years ago