Answer:
Answers are in the explanation
Explanation:
Based on the reaction:
CF₄ + 2Br₂ → CBr₄ + 2F₂
The mole ratio of CF₄ is:
CF₄:Br₂ = 1:2
CF₄:CBr₄ = 1:1
CF₄:F₂ = 1:2
<em>Moles F2:</em>
Molar mass CF₄: 88.0g/mol
57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =
<h3>1.30 moles F₂</h3><h3 />
<em>Mass Br2:</em>
Molar mass CBr₄: 331.63g/mol
250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =
1.51 moles Br₂ * (159.808g / mol) =
<h3>241g Br2</h3><h3 /><h3 />
<em>Moles F2:</em>
4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =
<h3>9.6 moles F₂</h3><h3 />
<em />
The bowl has more volume, the bearing has more volume. The mass is bigger for the bearing because it is heavier than the bowl. It is made of metal and the weight of it is greater than the bowl.(the body shape).
Answer:
First, you have to analyze your problem or question. After you research and collect data about your topic, create a hypothesis to test to try and find the answer. After testing your hypothesis, come up with a conclusion based on the results.
<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61
<u>Explanation:</u>
We are given:
Initial moles of iodine gas = 0.100 moles
Initial moles of hydrogen gas = 0.100 moles
Volume of container = 1.00 L
Molarity of the solution is calculated by the equation:
Equilibrium concentration of iodine gas = 0.0210 M
The chemical equation for the reaction of iodine gas and hydrogen gas follows:
<u>Initial:</u> 0.1 0.1
<u>At eqllm:</u> 0.1-x 0.1-x 2x
Evaluating the value of 'x'
The expression of 
for above equation follows:
![K_c=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
![[HI]_{eq}=2x=(2\times 0.079)=0.158M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D2x%3D%282%5Ctimes%200.079%29%3D0.158M)
![[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D%280.1-x%29%3D%280.1-0.079%29%3D0.0210M)
![[I_2]_{eq}=0.0210M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.0210M)
Putting values in above expression, we get:
Hence, the value of equilibrium constant for the given reaction is 56.61
B. 0.72 mol NaCl
http://www.convertunits.com/from/grams+NaCl/to/moles
