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vfiekz [6]
3 years ago
8

All substances can be classified as _____?

Chemistry
2 answers:
Alex73 [517]3 years ago
8 0
I believe that the answer is that, all substances can be classified as either organic or inorganic substances.
 Organic compound are a large class of gaseous, liquid, or solid compounds whose molecules contain one or more carbon atoms that are covalently linked to atoms of other elements, mainly, hydrogen, oxygen or nitrogen. Inorganic compounds on other hand are compounds with no carbon element on them, such as water. 
kakasveta [241]3 years ago
5 0

Answer: Organic or inorganic

Explanation: All the substances can be classified into two categories one is organic and other one is inorganic.

The substances that is made up of carbon atoms and hydrogen atoms to from hydrocarbon. These substances are known as organic compounds. Example: nucleic acid, fatty acid, et cetera.

Inorganic compounds does not contain carbon in it. It might have some carbon atoms but the amount of carbon is so low that it cannot be used to form bonds. Example: Salt, metal et cetera.

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In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
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Use the formula E=mc^2
energy given=<span>8.1 x 10^16 joules
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plug in the values we'll get mass=<span>9.0 x 10-1 kg</span>

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2 years ago
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The region in which an electron is likely to be found is known as a(n) ____________.
Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

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2 years ago
How do white blood cells fight pathogens?
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A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
dexar [7]

Answer:

5.758  is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d =998.2 kg/m^3

1 kg = 1000 g

1 m^3=10^6 cm^3

998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3

Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

Volume of metal = v' =\frac{M'}{d'}

Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

=d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3

5 0
2 years ago
1.) 3.3482 hL =__________nL
Taya2010 [7]

Answer:

334820000000nL

Explanation:

Since 1hL=100000000000nL

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