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RUDIKE [14]
2 years ago
14

Calculate the root mean square velocity, in m/s, of carbon dioxide molecules at 100.0

Chemistry
1 answer:
spayn [35]2 years ago
8 0

Answer:

459.8m/s

Explanation:

T=Temperature in Kelvin

M=molar mass in kg/mol

Molar mass of CO2,

mm=44.01g/mol

=0.04401kg/mol

T =100.0C

= (100.0 +273) K

=373K

So,

vrms= sqrt(3×R×T/M)

vrms=sqrt(3×8.314×373.0/0.04401)

=459.8m/s

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What is the charge of the ions formed by Na and by Cl?
Alexxandr [17]

Answer:

Na+ is positively charged as it loses an electron

Cl- is negatively charged as it gains an electron

3 0
2 years ago
Ammonia gas decomposes to form nitrogen and hydrogen gases. NH3(g) → N2(g) 3H2(g) If the nitrogen gas is collected in a rigid 2
sveticcg [70]

Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas (\rm N_{2}) in the cylinder is 1.63 moles.

<h3>What is the ideal gas equation?</h3>

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

\rm PV = nRT

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

Gas constant (R)=  0.08206

Substituting values  in the equation:

\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}

Therefore, 1.63 moles are produced.

Learn more about ideal gas equation here:

brainly.com/question/26720901

6 0
2 years ago
Which is a reason that a chemical engineer would use a rate law for a reaction in a chemical plant?
Harrizon [31]
<span>A.to calculate the amount of product that would form

</span>
5 0
3 years ago
Read 2 more answers
A chemical equation is shown: C2H4 + O2 → CO2 + H2O According to the law of conservation of mass, how many atoms of oxygen exist
astraxan [27]

Answer:

6 oxygens on the product side

Explanation:

1) balance the equation:

C2H4 + 3O2 → 2CO2 + 2H2O

2) calculate the number of oxygens on the product side

2CO2=4

2H2O=2

6 0
3 years ago
the element carbon has two common isotopes: C-12 (12 U) AND C-13 (13.003355 U). IF THE AVERAGE ATOMIC MASS OF CARBON IS 12.0107
oksian1 [2.3K]

Answer:

The percent isotopic abundance of C- 12 is 98.93 %

The percent isotopic abundance of C- 13 is 1.07 %

Explanation:

we know there are two naturally occurring isotopes of carbon, C-12 (12u)  and C-13 (13.003355)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 13.003355

1-x for isotopes having mass 12

The average atomic mass of carbon is 12.0107

we will use the following equation,

13.003355x + 12 (1-x) = 12.0107

13.003355x + 12 - 12x = 12.0107

13.003355x- 12x = 12.0107 -12

1.003355x = 0.0107

x= 0.0107/1.003355

x= 0.0107

0.0107 × 100 = 1.07 %

1.07 % is abundance of C-13 because we solve the fraction x.

now we will calculate the abundance of C-12.

(1-x)

1-0.0107 =0.9893

0.9893 × 100= 98.93 %

98.93 % for C-12.

7 0
3 years ago
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