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1 year ago

Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?

Chemistry

2 answers:

EastWind [94]1 year ago

7 0

Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.

Explanation:

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Kruka [31]1 year ago

3 0

Malleability is the ability of a metal to be hammered or rolled into thin sheets. Gold and silver are two examples of malleable metals.

Ductility is the ability of a metal to be drawn into thin wire. Copper and gold are two examples of ductile metals.

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The number of protons and neutrons combined in an atom of a particular element

Kobotan [32]

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3 years ago

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

sertanlavr [38]

Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

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2 years ago

NEED HELP FAST!!

koban [17]

Answer:

I'm pretty sure that's right.

Explanation:

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2 years ago

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Sergio039 [100]

Answer: is neither an acid nor a base

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