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olga nikolaevna [1]
1 year ago
13

Explain the terms physical properties of metals Malleability and ductility, and how they used in daily life situation ?​

Chemistry
2 answers:
EastWind [94]1 year ago
7 0

Answer:

Malleability means that metals can be hammered into sheets and foils. For example, aluminium foils are used for wrapping food stuffs, silver foils are used for decorative purposes on sweets and fruits. Ductility means that metals can be drawn into wires. Gold and silver wires are used in ornaments.

and For jewellery and ornaments, gold, platinum and silver are being used. For building purposes, iron and steel can be used. Iron and aluminium are used as utensils. The thermometer uses mercury and helps to monitor the temperature.

Explanation:

please rate as brainliest

Kruka [31]1 year ago
3 0
Malleability is the ability of a metal to be hammered or rolled into thin sheets. Gold and silver are two examples of malleable metals.

Ductility is the ability of a metal to be drawn into thin wire. Copper and gold are two examples of ductile metals.
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A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  50.0 kPa

P_2 = final pressure of gas = 80.0 kPa

V_1 = initial volume of gas = 80.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas = 320K

Now put all the given values in the above equation, we get:

\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}

V_2=53.3ml

The new volume is 53.3 ml

4 0
3 years ago
How many liters of CO2 are in 4.76 moles? (at STP)
dem82 [27]

<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L

<u>Explanation:</u>

We are given:

Moles of carbon dioxide = 4.76 moles

<u>At STP:</u>

1 mole of a gas occupies a volume of 22.4 Liters

So, for 4.76 moles of carbon dioxide gas will occupy a volume of = \frac{22.4L}{1mol\times 4.76mol=106.624L

Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L

6 0
3 years ago
2. Chromium+oxygen - chromium(III) oxide <br>balanced​
sesenic [268]

Answer:

4Cr + 3O2 —> 2Cr2O3

Explanation:

Information from the question include:

Chromium + oxygen -> chromium(III) oxide

From the word equation given above, the equation can be written as follow:

Cr + O2 —> Cr2O3

The equation can be balance by doing the following:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:

Cr + 3O2 —> 2Cr2O3

Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:

4Cr + 3O2 —> 2Cr2O3

Now the equation is balanced

3 0
3 years ago
A graduated cylinder is filled 25.0 mL with water and a piece of granite is placed in the cylinder, displacing the level to 37.2
kvv77 [185]

The volume  of the granite piece  in Cm³  is 12.2 cm³

 <u><em>calculation</em></u>

volume of granite = (volume of cylinder after placing granite - volume  of  cylinder  before  placing  granite

 = 37.2 ml - 25.0 ml = 12.2 ml


convert ml  to Cm³

that is 1 ml = 1 cm³

       12.2 ml =  ? cm³

<em>by cross  multiplication</em>

=(12.2 ml x 1 cm³) / 1 ml = 12.2 cm³


3 0
3 years ago
Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.
NARA [144]
PH is the test of acidity or basicity of a solution. it follows the formula: 
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case. 

By literature, Ka of HF is 3.5*10^-4 
<span>pKa= -log(Ka)=</span><span> 3.46 </span>

<span>pH = pKa + log [NaF / [HF] </span>

4.05 = 3.46 + log [NaF / [HF] 

log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
4 0
3 years ago
Read 2 more answers
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