Answer:
0.1105 moles per 130 ml
Explanation:
For 1 L (1000) of solution, no of moles are = 0.85
For 1 ml of solution, no of moles are = 0.85/1000 moles
For 130 ml of solution, no of moles are= 0.85/1000 x 130
= 0.1105 moles per 130 ml
Given :
Temperature, T = 55° C = ( 55 + 273 ) K = 328 K .
Volume of container, V = 28.9 dm³ = 0.0289 m³ .
Pressure, P = 144 kPa = 144000 Pa .
To Find :
Number of moles of nitrogen gas.
Solution :
We know, by ideal gas equation :
PV = nRT ( R ( universal gas constant ) = 8.31 J K⁻¹ mol⁻¹ .
Therefore, number of moles of nitrogen gas is 1.53 moles.
Answer:
1) Increases
2) decreases
3) increases
4) decreases
Explanation:
When the intermolecular forces in a liquid increases, the greater vapour pressure of the liquid decreases accordingly.
Since the vapour pressure is proportional to temperature, as temperature increases, the vapour pressure increases alongside.
As intermolecular forces increases, the boiling point increases accordingly since more energy is required to break intermolecular bonds.
Lastly, the greater the surface area, tell greater the vapour pressure since more liquid surface area is now available.
Answer:
Pioneer species I believe.
Explanation:
