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Eva8 [605]
3 years ago
12

A ray diagram for a refracted light ray is shown.

Physics
1 answer:
Rina8888 [55]3 years ago
7 0

The dashed line represents the<u> normal </u>to the boundary

Explanation:

Refraction is a phenomenon that occurs when a ray of light crosses the interface between two mediums.

When this occurs, the ray of light changes direction and speed.

The new direction of the ray of light is given by Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1 is the index of refraction of the 1st medium

n_2 is the index of refraction of thre 2nd medium

\theta_1 is the angle of incidence, which is the angle between the direction of the incident ray and the normal to the boundary

\theta_2 is the angle of refraction, which is the angle between the direction of the refracted ray and the normal to the boundary

The index of refraction of a medium is the ratio between the speed of light in a vacuum (c) and the speed of light in that medium (v):

n=\frac{c}{v}

The figure in the question is missing, however you can find it in attachment.

We see that the dashed line is perpendicualr to the boundary between the two mediums, so it represents the normal.

So, the correct answer is

Normal

We note that in this case the ray of light bends towards the normal, this means that \theta_2, therefore the second medium has a larger index of refraction (n_2>n_1).

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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Density can be kg/m^3 or g/cm3
In g/cm3 density =mass /volume =111g/23cm3
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In kg/m3,density=mass/volume. converting mass in grams to kg, 1000g=1kg,111g=0.111kg.
cm3 to m3, 1cm3=10^-6m3, 23cm3=0.000023m3
density=0.111kg/0.000023m3 or 2.3*10^-5=4,826.1kg/m3.

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An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert
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Answer:

The compression in the spring is 5.88 meters.                

Explanation:

Given that,

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Height of the car, h = 19 m

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We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

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