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4 years ago

A ray diagram for a refracted light ray is shown.

Physics

1 answer:

Rina8888 [55]4 years ago

7 0

The dashed line represents the<u> normal </u>to the boundary

Explanation:

Refraction is a phenomenon that occurs when a ray of light crosses the interface between two mediums.

When this occurs, the ray of light changes direction and speed.

The new direction of the ray of light is given by Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

$n_1$ is the index of refraction of the 1st medium

$n_2$ is the index of refraction of thre 2nd medium

$\theta_1$ is the angle of incidence, which is the angle between the direction of the incident ray and the normal to the boundary

$\theta_2$ is the angle of refraction, which is the angle between the direction of the refracted ray and the normal to the boundary

The index of refraction of a medium is the ratio between the speed of light in a vacuum (c) and the speed of light in that medium (v):

$n=\frac{c}{v}$

The figure in the question is missing, however you can find it in attachment.

We see that the dashed line is perpendicualr to the boundary between the two mediums, so it represents the normal.

So, the correct answer is

Normal

We note that in this case the ray of light bends towards the normal, this means that $\theta_2$ , therefore the second medium has a larger index of refraction ( $n_2>n_1$ ).

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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Which one of the following parenting factors is associated with improved IQ scores in children?

lapo4ka [179]

I would say B. A stable home and varied activities

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3 years ago

You are working as a summer intern for the Illinois Department of Natural Resources (DNR) and are assigned to some initial work

hammer [34]

Answer:

1) F = 71.6 N , 2) F = 120.2 N , 3) P_m= 68.600 Pa, 4) V = 2.4210-5 m³

Explanation:

This is a problem of fluid mechanics, to find the force we must use its definition

P = F / A

F = P A

The area of the circular pipe is

A = π r² = π d²/4

The pressure is given by the expression

P = P_atm + ρ g h

1) the force on the outer side is

P = P_atm

we substitute in the expression of force

F = P_atm π d² / 4

let's calculate

F = 1,013 10⁵ π 0.03²/4

F = 7.16 10¹ N

F = 71.6 N

2) the force on the inner side

the pressure

P = P_atm + ρ g h

P = 1,015 10⁵ + 1,000 9.8 7

P = 1,701 10⁵ Pa

F = 1,701 10⁵ π 0.03² / 4

F = 1,202 10²

F = 120.2 N

3) manometric pressure

Pm = ρ g h

P m = 1000 9.8 7

P_m= 68.600 Pa

4) In this part they ask for the volume that comes out in time t= 3 h

to calculate this volume we can use the flow ratio

Q = A v

V t = A v

V = A v / t

sent is the velocity of the water that comes out, to calculate it we use the Bernoulli equation

we will use index 1 for the lake surface and ionice 2 apa the position of the plug

P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂

As the lake has much more capacity than the pipeline, the velocity of the surface of the lake is peeling, in this case we approximate it steel

(P₁-P₂) + ρ G (y₁ -y₂) = ρ g v₂²

1000 9.8 v₂² = ρ g h + 1000 9.8 (7-0)

9800 v₂² = 1000 9.8 7 + 68600

v₂ = √ (137200)

v₂ = 370.4 m / s

t = 3 h (3600s / h) = 10800 s

we substitute in the volume equation

V = π d²/4 370.4 / 10800

V = 2.4210-5 m³

4 0

3 years ago

The slope of a line on a distance-time graph represents _____. distance time displacement speed

lisabon 2012 [21]

Answer:

speed

Explanation:

The slope of a line on any distance-time graph represents the speed of the object.

Velocity only comes in when there is speed of the object in a particular direction.

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3 years ago

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Nina [5.8K]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

a man drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 N at 38°. what is the coefficient of friction?

lesantik [10]

Answer:

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let $f$ be frictional force acting in the backward direction as shown. Let the coefficient of friction be $\mu$ . Let $N$ be the normal reaction force acting on the bag.

Given:

Mass of the bag is, $m=8.10\textrm{ kg}$

Force acting at $\theta = 38$ ° is $F= 29.5\textrm{ N}$

Acceleration due to gravity is, $g=9.8\textrm{ }m/s^{2}$

The force F can be resolved into its components as $F_{x}=F \cos \theta$ and $F_{y}=F \sin \theta$

Therefore,

$F_{x}=29.5\cos(38)=23.25\textrm{ N}\\F_{y}=29.5\sin(38)=18.16\textrm{ N}$

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

$N+F_{y}=mg\\N=mg-F_{y}=8.10\times 9.8-18.16\\N=79.38-18.16=61.22\textrm{ N}$

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

$f=F_{x}\\f=23.25\textrm{ N}$

Now, frictional force is given as:

$f=\mu N\\\mu = \frac{f}{N}=\frac{23.25}{61.22}=0.38$

Therefore, the coefficient of friction is 0.38.

8 0

4 years ago