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svetlana [45]
4 years ago
14

Why doesn’t air pressure crush an empty soft-drink can as you drive down a mountain?

Chemistry
1 answer:
Vadim26 [7]4 years ago
4 0

Answer:

The air pressure on the inner side of the can balances that on the outside of the can.

Explanation:

Indeed the air pressure might crush a properly-sealed air-tight can during the descent. The reason is that the air pressure on the outside of the can exceeds that on the inside. The force that pushes the wall inwards exceeds the force that pushes the wall outwards. It's the pressure difference that crushes the can. However, that's not exactly the case for the "empty soft-drink can" here.

The question states that the can is already "empty." Therefore, it is quite reasonable to assume that the can was already opened. In other words, the can would no longer be air-tight. Air particles could freely enter and leave the can. As a result, when the can is brought down a mountain, air enters the can. As long as the can stays open, there would be enough air particles on the inside to balances the pressure. A pressure difference will not build up. That ensures that the can stays intact.

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Your answer is (4) 4, because the alpha particle is a helium nucleus (either an ion or an ejected particle from alpha decay), and it has a mass number of 4, being consisted of four nucleons, (2 protons and 2 neutrons).
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2 years ago
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3 years ago
cooling a sample of matter from 70°c to 10°c at constant pressure causes its volume to decrease from 873.6 to 712.6 cm3. classif
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Explanation:

Expression for the coefficient of thermal expansion is as follows.

           \alpha = \frac{1}{V}(\frac{\Delta V}{\Delta T})

where,   V = initial volume

          \Delta V = Final volume - initial volume

                      = (712.6 - 873.6) cm^{3}

                      = -161 cm^{3}

Now, we will calculate the change in temperature as follows.

          \Delta T = Final temperature - Initial temperature

                       = (10 + 273) K - (70 + 273) K

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Substituting these values into the equation as follows.

     \alpha = \frac{1}{873.6} \times (\frac{161}{60}) K^{-1}

                 = 0.00307 K^{-1}

It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.

3 0
4 years ago
How many Protons, electrons, and neutrons are in Dysprosium? <br><br> EASY POINTS?
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Answer:

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Explanation:

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