True or false the fission of a nucleus is accompanied by the release of very little energy
1 answer:
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Answer:
b)15.0°C
Explanation:
Specific Heat of Water=4.2 J/g°C
This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.
∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.
80×4.2 J=336 J
Total Energy Provided=1680 J
The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}
Temperature increase=
=5°C
Initial Temperature =10°C
Final Temperature=Initial + Increase in Temperature
=10+5=15°C
Answer:
1) The new pressure of the gas is 500 kilopascals.
2) The final volume is 1.44 liters.
3) Volume will decrease by approximately 67 %.
4) The Boyle's Laws deals with pressures and volumes.
Explanation:
1) From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that ,
and
, then the new pressure of the gas is:
The new pressure of the gas is 500 kilopascals.
2) Let suppose that gas experiments an isothermal process. From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that ,
and
then the new volume of the gas is:
The final volume is 1.44 liters.
3) From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that , then the volume ratio is:
Volume will decrease by approximately 67 %.
4) The Boyle's Laws deals with pressures and volumes.