Look first for the relation between deBroglie wavelength (λ) and kinetic energy (K):
K = ½mv²
v = √(2K/m)
λ = h/(mv)
= h/(m√(2K/m))
= h/√(2Km)
So λ is proportional to 1/√K.
in the potential well the potential energy is zero, so completely the electron's energy is in the shape of kinetic energy:
K = 6U₀
Outer the potential well the potential energy is U₀, so
K = 5U₀
(because kinetic and potential energies add up to 6U₀)
Therefore, the ratio of the de Broglie wavelength of the electron in the region x>L (outside the well) to the wavelength for 0<x<L (inside the well) is:
1/√(5U₀) : 1/√(6U₀)
= √6 : √5
Answer:
The change in momentum is 
Explanation:
From the question we are told that
The mass of the probe is 
The location of the prob at time t = 22.9 s is 
The momentum at time t = 22.9 s is 
The net force on the probe is 
Generally the change in momentum is mathematically represented as
The initial time is 22.6 s
The final time is 22.9 s
Substituting values
The electrical charge of particles. The total number of electrons in an atom is always the same as the number of protons in the nucleus. This means atoms have no overall electric charge. The number of protons in an atom is called its atomic hater number.
Answer:
The initial volume of the system is 2.7 L
Explanation:
The change in internal energy is given by;
ΔU = Q - W
where;
Q is the heat absorb from the surrounding
W is the work done by the system
Given;
ΔU = -107.6 J
Q = 59 J
W = ?
W = Q- ΔU
W = 59J - (-107.6)
W = 166.6 J
Work done is given by;
W = PΔV
W = P(V₂ - V₁)
101.325 Joules = 1 L.atm
166.6 Joules = ?
= 1.644 L.atm
1.644 L.atm = 0.543 atm(57.7L - V₁)
57.7L - V₁ = (1.644 L.atm) / (0.543 atm)
57.7L - V₁ = 3.0 L
V₁ = 57.7L - 3.0 L
V₁ = 2.7 L
Therefore, the initial volume of the system is 2.7 L
