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olga55 [171]
3 years ago
10

How was Mendeleev's table different from Meyer's table? A. Mendeleev did not arrange according to chemical properties. B. Meyer

did not arrange by atomic mass but Mendeleev did. C. Meyer did not leave gaps while Mendeleev did. D. Mendeleev did not arrange according to physical properties.
Physics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer: C. Meyer did not leave gaps while Mendeleev did.

Explanation: Mendeleev's table was table different from Meyer's table because Meyer did not leave gaps while Mendeleev did.

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If v =5.00 meters/second and makes an angle of 60 with the negative direction of the y-axis coalculate the possible values of vx
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An angle of 60 degrees with the negative y-axis could mean 60 degrees clockwise or counterclockwise, which translates to two possible angles (starting from the positive x-axis and moving counterclockwise) of 210 degrees or 330 degrees.

Then the horizontal component v_x of a velocity vector \mathbf v with magnitude 5.00\,\dfrac{\mathrm m}{\mathrm s} could be one of two expressions:

v_x=\left(5.00\,\dfrac{\mathrm m}{\mathrm s}\right)\cos210^\circ=-4.33\,\dfrac{\mathrm m}{\mathrm s}

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Answer these questions "type of heat transfer that occurs between the sun and venus" "measure of the average value of the kineti
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A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential differen
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The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

  • Work function is a material property defined as the minimum amount of energy  required to infinitely remove electrons from the surface of a particular solid.
  • The potential difference required to support all emitted electrons is called the stopping potential which is given by v_0=\frac{K.E_m_a_x}{e} .....(1)
  • where v_0 is the stopping potential and e is the charge of the electron given by 1.6\times10^-^1^9 .

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation  is given by:

K.E_m_a_x=E-\phi      ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

  ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV

As we know that E=\frac{hc}{\lambda}  ....(3)

where Speed of light,c = 3\times10^8 m/s and Planck's constant , h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs

From equation (3) , we get

\lambda=\frac{hc}{E} \\\\\lambda=\frac{  4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm

Learn about more einstein photoelectric equation  here:

brainly.com/question/11683155

#SPJ4

8 0
1 year ago
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